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Warning: ereg(): REG_EPAREN in

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Oct 13.2005

i have this line of code
Warning: ereg(): REG_EPAREN in update.php on line 7

[code=php]
/* 7 */ if (ereg(“/d(1,3}.d{2}/”, $pay3))
{
echo “hello”;
}
[/code]

everything I see on the web says that it is a peren issue but the ereg function I thought took 2 strings.

string 1 = “/d(1,3}.d{2}/”
string 2 = $pay3

what am I doing wrong???

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PHP

6 Comments(s) ↴

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@bokehOct 13.2005 — ereg() doesn't need delimiters

Also you have miss matched brackets:

This: d[B]([/B]1,3}.d{2}

should be: d[B]{[/B]1,3}.d{2}
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@DARTHTAMPONauthorOct 13.2005 — now if i do an echo ereg("d{1,3}.d{2}", $pay3); it I thought would have printed true or false, but it does not.

why?
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@bokehOct 13.2005 — You cannot echo a boolean. If you want to see a print out of TRUE/FALSE use:
[code=php]var_dump(ereg("d{1,3}.d{2}", $pay3));[/code]
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@DARTHTAMPONauthorOct 13.2005 — ok so now I added
[code=php]
var_dump(ereg("d{1,3}.d{2}", $pay3));
[/code]

$pay3 = 0.36

and the dump prints out bool(false)

why is this when the regexp should
<i>
</i>d{1,3} = 0
. = .
d{2} = 36


This should come out true not false.
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@bokehOct 13.2005 — d is part of PCRE so it can be used with preg_match() etc but not ereg().

Try this instead: [code=php]var_dump(ereg('[0-9]{1,3}.[0-9]{2}', '0.36'));[/code]

By the way ereg() returns bool(false) on failure and INT(1) on success.
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@DARTHTAMPONauthorOct 14.2005 — thank you vary much bokeh for all your help. I really appreciate it.
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