@NogDogAug 07.2005 — #Probably the closest you could come would be every other (or every third) day of the month. The pattern would break down at the end of each month if it's not divisible evenly by two (or three): <i> </i>30 1 2-30/2 * * echo "run at 1:30am on even-numbered days of the month"
@Stephen_PhilbinAug 07.2005 — #How about doing it in a two-step approach?
Could you make a shell script that, when executed, sets up the desired cron job if absent, and deletes the desired cron job if present. Then have a daily cron job to execute that shell script.That way the first one alternates the presence of the second job which would then get executed one minute later if present by the previous one writing it. Does that make sense or should I just give up trying to speak English?
@Stephen_PhilbinAug 07.2005 — #Oh yeah. How ridiculously obvious. I'm not even gonna try and think about why I thought of the solution I did and not the one you thought of. It's bound to hurt.
