Php -q

@LiLcRaZyFuZzYJan 14.2005 — #from http://www.phpbuilder.com/annotate/message.php3?id=1016610
Message # 1016610:

Date: 05/29/03 16:21

By: Far Side

Subject: RE: php -q and php-4.0.6

>

My script starts with:
>--

#!/usr/local/bin/php -q
>--

But when I execute the code from the >commandline:
>--

php test.php > test.html
>---

Well, duh!

[b]the first line just tells posix based systems (like *nix) that it should use the PHP interpretter to process this script if it has been started from the console, and have the execute/search attribute set, by just entering:

$ ./test.php > test.html

to run it on W32 systems or by executing the php command you'll have to enter:

php -q test.php > test.html[/b][/QUOTE]

Php -q

1 Comments(s) _↴

My script starts with:
>--

#!/usr/local/bin/php -q
>--

But when I execute the code from the >commandline:
>--

php test.php > test.html
>---

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Php -q

1 Comments(s) ↴

My script starts with: >--

#!/usr/local/bin/php -q >--

But when I execute the code from the >commandline: >--

php test.php > test.html >---

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Success!

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Version

1 Comments(s) _↴

My script starts with:
>--

#!/usr/local/bin/php -q
>--

But when I execute the code from the >commandline:
>--

php test.php > test.html
>---

Also in #PHP _↴