A new image each time page is reloaded???

@TheBearMayDec 16.2004 — #Good place to learn JS online is: http://www.w3schools.com/js/default.asp

For a new image each time you'll need to do two things. First create an array of images, and secondly store the image number in a cookie so you know where you left off.

[code=php]
 <?xml version="1.0" encoding="UTF-8"?>
 <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.1//EN" "http://www.w3.org/TR/xhtml11/DTD/xhtml11.dtd">
 <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en">
 <head>
 <script type="text/javascript">
 function getCookieVal (offset) {
 var endstr = document.cookie.indexOf (";", offset);
 if (endstr == -1)
 endstr = document.cookie.length;
 return unescape(document.cookie.substring(offset, endstr));
 }
 
 function getCookie (name) {
 var arg = name + "=";
 var alen = arg.length;
 var clen = document.cookie.length;
 var i = 0;
 while (i < clen) {
 var j = i + alen;
 if (document.cookie.substring(i, j) == arg)
 return getCookieVal (j);
 i = document.cookie.indexOf(" ", i) + 1;
 if (i == 0) break;
 }
 return null;
 }
 
 function setCookie (name, value) {
 var argv = setCookie.arguments;
 var argc = setCookie.arguments.length;
 var expires = (argc > 2) ? argv[2] : null;
 var path = (argc > 3) ? argv[3] : null;
 var domain = (argc > 4) ? argv[4] : null;
 var secure = (argc > 5) ? argv[5] : false;
 document.cookie = name + "=" + escape (value) +
 ((expires == null) ? "" : ("; expires=" + expires.toGMTString())) +
 ((path == null) ? "" : ("; path=" + path)) +
 ((domain == null) ? "" : ("; domain=" + domain)) +
 ((secure == true) ? "; secure" : "");
 }
 
 function newImage(){
 var imgArr=["images/img1.gif", "images/img2.gif"];
 var arrInx=getCookie("lastImage");
 if (arrInx==NaN || arrInx==null) arrInx=-1;
 arrInx++;
 if (arrInx >= imgArr.length) arrInx = 0;
 setCookie("lastImage", arrInx);
 document.getElementById("imgRotate").src=imgArr[arrInx];
 }
 
 
 </script>
 </head>
 
 <body onload="newImage();">
 
 <img id="imgRotate" />
 </body>
 </html>[/code]

@palmertiresauthorDec 16.2004 — #Thank you! I will have to try this out later. I have to admit, javascript is a little daunting (but, I am hoping at some point it will click for me).

@TheBearMayDec 16.2004 — #Take it one step at a time and it'll click at some point. Good Luck.

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