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Variable literals or references?

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Jun 02.2009

Suppose I have this:

[code]
$x = ‘qwerty’;
$y = &$x;
$z = $y;
[/code]

Will $z contain the actual value ‘qwerty’ or will it also be a reference to $x just like $y is?

Thanks

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PHP

3 Comments(s) ↴

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@MindzaiJun 02.2009 — $z will be the [B]value[/B] of $y. If you were to change $x or $y, $z would still == 'qwerty', but $x and $y would == the new value.
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@SnartmanauthorJun 02.2009 — Thanks. I guess $z = &$y is the way to go then.
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@NogDogJun 02.2009 — Presumably you have some reason for this? After all, simply using $x without any references is simpler, cleaner, and easier to maintain/debug.
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