/    Sign up×
Community /Pin to ProfileBookmark

imlib_load_image() return value?

When i create a image through imlib it not return resource but the gd and imagick return resource how to check the imlib return is resource or not?

sample
========

if(is_resource($a))
echo “<br>is gd resource<br>”;
else
echo “<br>not gd resource<br>”;
echo “imagickresource->”.$b = Imagick_readimage(“redeye.jpg”);
if(is_resource($b))
echo “<br>is imagick resource<br>”;
else
echo “<br>is not imagick resource<br>”;
echo “imlibresource->”.$c = imlib_load_image(“redeye.jpg”);
if(is_resource($c))
echo “<br>is imlib resource<br>”;
else
echo “<br>is not imlib resource<br>”;

to post a comment
PHP

0Be the first to comment 😎

×

Success!

Help @tvarghese spread the word by sharing this article on Twitter...

Tweet This
Sign in
Forgot password?
Sign in with TwitchSign in with GithubCreate Account
about: ({
version: 0.1.9 BETA 5.25,
whats_new: community page,
up_next: more Davinci•003 tasks,
coming_soon: events calendar,
social: @webDeveloperHQ
});

legal: ({
terms: of use,
privacy: policy
});
changelog: (
version: 0.1.9,
notes: added community page

version: 0.1.8,
notes: added Davinci•003

version: 0.1.7,
notes: upvote answers to bounties

version: 0.1.6,
notes: article editor refresh
)...
recent_tips: (
tipper: @AriseFacilitySolutions09,
tipped: article
amount: 1000 SATS,

tipper: @Yussuf4331,
tipped: article
amount: 1000 SATS,

tipper: @darkwebsites540,
tipped: article
amount: 10 SATS,
)...