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I am not sure if this is a MySql or php problem.

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Sep 13.2006

Hi

I am not sure if this is a MySql or php problem.

How do I check if a mysql table is empty?

I have used this code:

[CODE]
$Exist = “SELECT * FROM log WHERE CName=’$CName’ AND League=’$Liga AND Day=’$Days'”;
$result = mysql_query($Exist);
$num=mysql_numrows($result);
[/CODE]

to search the table for the content but if the table is empty with no data rows in it I get the following error.

Warning: mysql_numrows(): supplied argument is not a valid MySQL result resource in C:XitamiwebpagesWPCricketData AdminAddresult.php on line 266

Line 266 is $num=mysql_numrows($result);

How do I prevent this error?

Pleas help.

to post a comment
PHP

3 Comments(s) ↴

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@pcthugSep 13.2006 — The mysql_numrows function is deprecated, use the mysql_num_rows function instead. Also make use of the mysql_errno and mysql_error functions.
[code=php]
$Exist = "SELECT * FROM log WHERE CName='$CName' AND League='$Liga AND Day='$Days'";
$result = mysql_query($Exist) or die(mysql_errno() . ": " . mysql_error() . "n");
$num = @mysql_num_rows($result);
[/code]
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@bokehSep 13.2006 — The mysql_numrows function is deprecated, use the mysql_num_rows function instead. Also make use of the mysql_errno and mysql_error functions.
[code=php]
$Exist = "SELECT * FROM log WHERE CName='$CName' AND League='$Liga AND Day='$Days'";
$result = mysql_query($Exist);
$num = @mysql_num_rows($result) or die(mysql_errno() . ": " . mysql_error() . "n");
[/code][/QUOTE]You should have the die statement on the query line.[code=php]$result = mysql_query($query) or die('etc');[/code]
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@pcthugSep 13.2006 — Careless mistake...
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