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Ajax: Handling a response that’s in the form of javascript code

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Jun 27.2006

Two questions on this subject:

First, I want the PHP to send this code for example:

document.getElementById(input).innerHTML =”<input type=”hidden” value =”something”>”

Notice that I already have the characters “, but if I echo that in php it will echo a simple “. How do I bypass that? ” ?

Let’s say I get that working:

How do I handle the response? How do I actually “run” that bit of javascript once i receive it?

Thanks.

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10 Comments(s) ↴

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@phpnoviceJun 27.2006 — [code=php]<?php
echo <<<END
document.getElementById(input).innerHTML = '<input type="hidden" value="something">';
END;
?>[/code]
When received via XMLHttpRequest, you must use [b]eval()[/b] to execute that code.
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@MonsieurRenardauthorJun 27.2006 — Many thanks as always.
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@phpnoviceJun 27.2006 — You're welcome.

Cheers.
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@MonsieurRenardauthorJun 27.2006 — I'm getting an error:

if (strEq($answers[$j][4], "Y")){echo &lt;&lt;&lt;END # error on this line
document.getElementById('message_$j').innerHTML = 'Correct';
END;}

parse error, expecting '," or ';"

What might be causing this?
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@phpnoviceJun 28.2006 — Don't try to compress your code so much:
[code=php]if (strEq($answers[$j][4], "Y")){
echo <<<END
document.getElementById('message_$j').innerHTML = 'Correct';
END;
}[/code]
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@MonsieurRenardauthorJun 28.2006 — Still has the same error on this line: echo <<<END

It doesn't seem to like this format. Is there any reason why it's doing this? Is there an alternative solution?
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@phpnoviceJun 28.2006 — Do you have it inside of PHP script tags?
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@MonsieurRenardauthorJun 28.2006 — Yeah, the rest of the code works fine.

It also works fine if I put it in simple echo "stuff" format but later I will need to echo longer stuff and characters like "
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@phpnoviceJun 28.2006 — Well, that [b]echo[/b] statement format comes right out of the PHP manual.

So, I don't know what to tell you. What version of PHP do you run?
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@netbuddyJun 28.2006 — It would be easier if you simply had a text file that you call and then pass into the browser interpreter.

By the looks of it, your request is returing something that the intrepreter in the browser does not understand, namely php when its expecting javascript.
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