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@NogDogMar 07.2006 — #
Personally, I find it easier to follow the code by not going in and out of PHP mode all the time, but that's more a matter of taste. Here's a cleaner way to do it:
@NogDogMar 07.2006 — #
passing variables into javascript.
I read another thread that seems to indicate that what I want to do can be done in php. I am quite new to php.
my page is at [url]http://www.stevelim.com/links/links.html
what I am trying to do is pass parameters from other pages which will determine which CSS id to hide and show.
here is the code that I think I should be using..
[CODE]<?php if($_GET[“type”] == “friends”){
?>
<div id=”friends” style=”display: ””>
<?php
} else {
<div id=”friends” style=”display: ‘none'”>
?>
<?php
}
?>
I get a parse error.
Thanks.
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@NogDogMar 07.2006 — #[code=php]
<?php if($_GET["type"] == "friends"){
?>
<div id="friends" style="display: ''">
<?php
} else {
?>
<div id="friends" style="display: 'none'">
<?php
}
?>
[/code]Personally, I find it easier to follow the code by not going in and out of PHP mode all the time, but that's more a matter of taste. Here's a cleaner way to do it:
[code=php]
<?php
$style = ($_GET["type"] == "friends") ? '' : 'style="display: none"';
echo "<div id="friends"$style>n";
?>
[/code]0
@NogDogMar 07.2006 — #I think I just need the syntax for the following pseudocode..
$style = ($_GET["type"] == "friends" [B]OR _no type exists[/B]) ? '' : 'style="display: none"';[/QUOTE]
[code=php]
$style = (!isset($_GET["type"]) or $_GET["type"] == "friends") ? '' : 'style="display: none"';
[/code]