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hi
i am having a JS code for validation some checkboxes like this….
——————————CODE—————————————
function val() // Function to call checkbox function (?)
{
if (!is_multiple_checked())
{
alert (‘Please Select Something’);
return false;
}
return true;
}
function is_multiple_checked() // Function to check that one or more radio buttons are selected
{
var formObj = document[‘form1’][‘sub[]’];
var count = 0;
for (i=0;i<formObj.length; i++)
{
if(formObj[i].type == ‘checkbox’)
if(formObj[i].checked)
count++;
}
if (count < 1)
return false;
else if(count >=1)
return true;
}
it is working fine for more than one checkbox ie when there are more than 1 checkbox and if i dont select anyone of them then it prints the alert msg. ; the problem is when there is only one checkbox and when i check it press the Submit button then also it is giving me the alert msg.
What can be the fault????
i am giving the code for checkboxes also(its the same one excepy it takes values from a file)
————————–CHECKBOX CODE——————————–
<?php
for($j=0;$j<$length-1;$j++)
{
$sub = $data[$j];
$subname = $mainh.$j; /////sub is the value i am taking 4m a file
?>
<input type=checkbox name=”sub[]” value=”<?php echo “$sub”; ?>” >
<?php echo “$sub”; ?><br>
<?php
} /////////////////////////////////////////// for ends
?>
ie when the value taken from file 4 “$sub” is one ,only one checkbox appears on the page and then that validation is giving me problem !!!!!!!!!!
can u do something???? u can take some values for “$sub” instead taking them from a file
-thanks
-ashish