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using min max functions

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Jan 26.2006

I have a small function that I am not sure how to proceed with..

I have four values of which I want the average of the middle two values

Something like this;

[code]
document.menter.Final.value = ( j1 + j2 + j3 + j4 – max (j1,j2,j3,j4) -min (j1,j2,j3,j4) ) /2 ;
[/code]

But as I understand it the min max functions only work with two values. So I am not sure how to do this. Thanks for your assistance.

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JavaScript

6 Comments(s) ↴

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@Orc_ScorcherJan 26.2006 — In recent JavaScript versions, Math.min and Math.max can take any number of arguments. Just prefix max and min in your code with 'Math.'.
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@DasherauthorJan 26.2006 — I can't find a reference that allows more than 2 values in the min max compare. So I tried this...
<i>
</i>Cmax1 = Math.max(jone,jtwo);
Cmax2 = Math.max(jthree,jfour);
CmaxF = Math.max(Cmax1,Cmax2);
Cmin1 = Math.min(jone,jtwo);
Cmin2 = Math.min(jthree,jfour);
CminF = Math.min(Cmin1,Cmin2);
Cmedian = (jone + jtwo + jthree + jfour - CmaxF - CminF);
document.menter.Final.value = Cmedian / 2 ;

But I get nonsense results like 5050495 for 10, 10, 10, 10.

[URL=http://developer.mozilla.org/en/docs/Core_JavaScript_1.5_Reference:Global_Objects:Math:max]On this page[/URL]

I found the comment "Because max is a static method of Math, you always use it as Math.max(), rather than as a method of a Math object you created."

I have no idea what that really statement means, but evidently I am doing it wrong. :-)
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@SelrachJan 26.2006 — Can we see the code for the page where you are calling this function? It looks like the code is right, but how are you setting jone, jtwo, jthree, and jfour?
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@DasherauthorJan 26.2006 — The values are inputted thusly;

in a form
<i>
</i>&lt;form name="menter" action="&lt;?php echo $PHP_SELF ?&gt;" method="post"&gt;
&lt;input value="0" name="J1" type="text" size='2' onFocus="startCalc();" onBlur="stopCalc();" /&gt;
// etc for each Jx
&lt;/form&gt;
// ******************
// in the javascript section
function calc(){
jone = document.menter.J1.value;
//etc for each jxxx.
}


FYI: The actual function is a bit more complicated. There is a switch statement that selects different math operations such as jone+jtwo+jthree or (jone +jtwo) /2 All of the switch statements work correctly except this one with the Math.max and Math.min .

I could post the enter javascript if it would help. I am thinking somehow I am not using the Math.max or Math.min methods correctly. I am not a frequent user of javascript. Most of my programming is done in PHP.

There are two other functions not shown: startCalc and stopCalc they work fine.
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@Orc_ScorcherJan 26.2006 — The values of input elements are strings, you need to convert them to numbers first. And trust me, max and min can handle more than 2 arguments. If you need a reference, http://windowssdk.msdn.microsoft.com/library/default.asp?url=/library/en-us/script56/html/f3ea1b8a-5fd0-482a-971b-b7f8e2b9b7eb.asp
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@DasherauthorJan 26.2006 — [B]Kaa_Ching [/B]

That was it! Works great now.

Thanks so much.

That would explain why I had to add quotes around my case 'x': statements too.
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