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Sort Copy of Array

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Nov 28.2005

I want to alphabetically sort a copy of an array, but keep the original intact.

[CODE]unsorted = new Array(50);
…
var sorted = unsorted.sort();[/CODE]

so sorted will be a sorted array
but unsorted will remain in the original order.

Is this possible without creating two arrays manually?

Thanks

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JavaScript

2 Comments(s) ↴

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@Orc_ScorcherNov 28.2005 — Sure, write your own sort function that doesn't copy in place. Quicksort is just a few lines in JavaScript. I don't know why you wouldn't want to create a copy of the unsorted array first, though:

sorted = unsorted.slice(0).sort()
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@digitalgravyauthorNov 28.2005 — Sure, write your own sort function that doesn't copy in place. Quicksort is just a few lines in JavaScript. I don't know why you wouldn't want to create a copy of the unsorted array first, though:

sorted = unsorted.slice(0).sort()[/QUOTE]
I would have no problem creating the copy first. Thanks Orc
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