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variable in function call problem

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Nov 06.2005

(before i start, I AM A COMPLETE NOOOOO?

everytime I have a variable in a function call i get an error

mysql_fetch_array(): supplied argument is not a valid MySQL

[code]
$checkemail = mysql_query(“SELECT email FROM users WHERE email=’$email'”);
$checkemail = mysql_num_rows($checkemail);
[/code]

anyone have any ideas what the problem is?

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PHP

1 Comments(s) ↴

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@ShrineDesignsNov 06.2005 — you are replacing the result (which mysql_fetch_array() needs in order to get data from mysql) from mysql_query() with the value returned from mysql_num_rows()

try[code=php]
// ...
$result = mysql_query("SELECT email FROM users WHERE email = '$email'");
$row_count = mysql_num_rows($result);
// ...
[/code]
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