PHP variable variables

@resullivanSep 28.2005

I am very agrivated by this and it is taking everything in me not to throw something.

[code=php] ${$temp . “[‘passyds’]”} += $passing[$i + 3]; print ${$temp . “[‘passyds’]”} . ” ” . $C0Palmer[‘passyds’];

${$temp . “[‘passyds’]”} prints the correct number $C0Palmer[‘passyds’]; prints nothing [/code]

$temp is definately C0Palmer. I did a strlen and it was the correct length(8) and I did print $temp and it showed that it was C0Palmer. I printed a list of all the variables and it showed that C0Palmer[‘passyds’] was there. Obviously there is a naming issue with the array but I have completely run out of ideas on how to find what the difference is. Any help would be much appreciated.

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PHP

16 Comments(s) _↴

@chrysSep 28.2005 — #Whatcha tryin to do?

An alternative to variable variables is using an array.. like

$vars["$variablename"] = $variablename;

GImme more details ?

@resullivanauthorSep 28.2005 — #The reason I can not do that is because the name like C0Palmer is going to have stats within the array $C0Palmer for examle $C0Palmer['passyds'].

@resullivanauthorSep 28.2005 — #Here is a bigger slice

[code=php]
 $passing = explode(" ", $temppass);
 $num = count($passing);
 for ($i = -10; $i < $num; $i += 10) {
 $temp = trim(str_replace(".", "", $passing[$i]));
 if (strlen($temp) != 0) {
 ${$temp . "['comp']"} += $passing[$i + 1];
 ${$temp . "['att']"} += $passing[$i + 2];
 ${$temp . "['passyds']"} += $passing[$i + 3];
 print ${$temp . "['passyds']"} . " " . strlen($temp) . " " . $temp;
 ${$temp . "['y/a']"} += $passing[$i + 5];
 ${$temp . "['sack']"} += $passing[$i + 6];
 ${$temp . "['ydsl']"} += $passing[$i + 7];
 ${$temp . "['td']"} += $passing[$i + 8];
 ${$temp . "['int']"} += $passing[$i + 9];
 }
 }
 [/code]

small explanation:

$temppass has a persons name then stats in row until another persons name comes up followed by their stats all seperated by spaces. The print statement is there for debugging purposes. ${$temp . "['passyds']"} prints the correct stat however if I look at the persons name for example C0Palmer and try $C0Palmer['passyds'] it returns nothing. I did a print_r of all defined variables and C0Palmer['passyds'] was one of them.

@chrysSep 28.2005 — #I believe it's a poor way to code (using variable variables).

What you can do is create a "person" object.

This way you can have $people[$lastname] be a refernce to an object of stats, or even another array...

so if I understand correctly, then you can do:

$people['jones']->sacks = $sacks;

$people['jones']->yards = $yards;

Do you capt?

@WebnerdSep 28.2005 — #$temp="craig";

${$temp}=Array();

${$temp}['passyds'] ="is cool";

echo $craig["passyds"];

Works fine. But I agree, an object would be a lot better way to go.

@resullivanauthorSep 28.2005 — #I will try that I just did not know of what you mentioned. Unfortanatly I will not be able to test it until sunday. I play fanatasy football on yahoo but you have to pay like 9.99 to be able to view live stats. Im cheap so i decided to make a script to view live stats via yahoo. You can go under an individual game to see individual player stats so I made a script that goes to yahoos nfl sports page. It find the active or just finished games and gathers the players stats for those games. It does all this fine but I have to clean up the data so I can use it. Actually I know a url of a previously played game so I am going to go force it into the script and try what you mentioned. Thanks!

p.s.

Hopefully this works because php variable variables agrivate me.

@WebnerdSep 28.2005 — #

[code=php]
 <?
 
 class Person{
 
 var $name;
 var $stats;
 
 function Person($name){
 $this->name=$name;
 $this->stats=Array();
 }
 
 function AssignStat($stat,$value){
 $this->stats[$stat]=$value;
 }
 
 }
 
 
 // Set the Object
 
 $temp="COPalmer";
 
 $p=new Person($temp);
 $p->AssignStat("comp",$passing[$i + 1]);
 $p->AssignStat("att",$passing[$i + 2]);
 $p->AssignStat("passyards",$passing[$i + 3]);
 // etc...
 
 // Print the Object
 
 echo $p->name;
 
 foreach($p->stats as $key=>$value){
 echo $key."=".$value."<br/>";
 }
 
 
 
 
 ?>[/code]

@resullivanauthorSep 28.2005 — #

[code=php]
 $temp="craig";
 
 ${$temp}=Array();
 
 ${$temp}['passyds'] ="is cool";
 
 echo $craig["passyds"];
 [/code]

I see a difference from this and what I have. If i made it like this it would probably work but I like to learn new things so I am going to do it the object way.

${$temp}['passyds'] ="is cool"; yours

${$temp . "['passyds']"} ="is cool"; mine

@resullivanauthorSep 28.2005 — #First off I would like to thank you for not flamming me about not using obeject oriented programming. Second, I know that this is the best way to do things but is tuff to make that transition when you do it more for fun than as a job. I have always used functions but have never really made that transition into fully object oriented.

@chrysSep 28.2005 — #

[code=php]
 <?
 
 class Person{
 
 var $name;
 var $stats;
 
 function Person($name){
 $this->name=$name;
 $this->stats=Array();
 }
 
 function AssignStat($stat,$value){
 $this->stats[$stat]=$value;
 }
 
 }
 
 
 // Set the Object
 
 $temp="COPalmer";
 
 $p=new Person($temp);
 $p->AssignStat("comp",$passing[$i + 1]);
 $p->AssignStat("att",$passing[$i + 2]);
 $p->AssignStat("passyards",$passing[$i + 3]);
 // etc...
 
 // Print the Object
 
 echo $p->name;
 
 foreach($p->stats as $key=>$value){
 echo $key."=".$value."<br/>";
 }
 
 
 
 
 ?>[/code]

[/QUOTE]

Yep, this is the right way to do it. Webnerd, can you help me out with my PHP compilation issue? It's driving me up the friggin wall.

@resullivanauthorSep 28.2005 — #so after the above is done how would I get C0Palmer passyds? Would it be

C0Palmer->stats['passyds']?

@chrysSep 28.2005 — #so after the above is done how would I get C0Palmer passyds? Would it be

C0Palmer->stats['passyds']?[/QUOTE]

Well, the way I'd do it (using that class) is:

$players['C0Palmer'] = new Player();

Then you access stats like

$players[C0Palmer]->passyds;

@resullivanauthorSep 28.2005 — #Maybe I am wrong but it seems as if I am going to need to still use a variable variable which seems to be for example $p. The reason is $temp is something that changes as the loop progresses. The array that is being looped through may look something like this:

C0Palmer

100

10

AnotherName

1

10

I do not see how I am going to be able to call back a specific stat at a later time based on the players name. In the above $p would refer to C0Palmer(name, stats) but there are going to be multiple names.

@resullivanauthorSep 28.2005 — #Just let me know if these changes I have made are completely stupid but from my small understanding of programming this is what I have changed.

[code=php]
 class Person{ 
 
 var $name; 
 var $stats; 
 
 function Person($name){ 
 $this->name=$name; 
 $this->stats=Array(); 
 } 
 
 function Person(){ 
 $this->stats=Array(); 
 } 
 
 function AssignStat($stat,$value){ 
 $this->stats[$stat]+=$value; 
 } 
 
 }
 
 $passing = explode(" ", $temppass);
 $num = count($passing);
 for ($i = -10; $i < $num; $i += 10) {
 $temp = trim(str_replace(".", "", $passing[$i]));
 if (strlen($temp) != 0) {
 if (!isset(${$temp})) {
 ${$temp}=new Person(str_replace("0", ". ", $temp)); 
 }
 ${$temp}->AssignStat("comp",$passing[$i + 1]); 
 ${$temp}->AssignStat("att",$passing[$i + 2]); 
 ${$temp}->AssignStat("passyards",$passing[$i + 3]); 
 ${$temp}->AssignStat("y/a",$passing[$i + 5]); 
 ${$temp}->AssignStat("sack",$passing[$i + 6]); 
 ${$temp}->AssignStat("ydsl",$passing[$i + 7]); 
 ${$temp}->AssignStat("td",$passing[$i + 8]); 
 ${$temp}->AssignStat("int",$passing[$i + 9]); 
 }
 }
 [/code]

@resullivanauthorSep 28.2005 — #I do not know if it is the best way but the above works. Thank you for all the help.

@WebnerdSep 28.2005 — #

[code=php]
 <?
 class Person{
 
  var $name;
  var $stats;
 
  function Person($name){
   $this->name=$name;
   $this->stats=Array();
  }
 
  function Person(){
   $this->stats=Array();
  }
 
  function AssignStat($stat,$value){
   $this->stats[$stat]+=$value;
  }
 
 }
 
 
 $people=Array();
 
 $passing = explode(" ", $temppass);
 
 $num = count($passing);
 
 for ($i = -10; $i < $num; $i += 10) {
 
  $temp = trim(str_replace(".", "", $passing[$i]));
 
  if (strlen($temp) != 0) {
 
   $name=str_replace("0", ". ", $temp);
 
   if(!isset($people[$name])){
   $people[$name]=new Person($name);
   }
  }
 
  $people[$name]->AssignStat("comp",$passing[$i + 1]);
  $people[$name]->AssignStat("att",$passing[$i + 2]);
  $people[$name]->AssignStat("passyards",$passing[$i + 3]);
  $people[$name]->AssignStat("y/a",$passing[$i + 5]);
  $people[$name]->AssignStat("sack",$passing[$i + 6]);
  $people[$name]->AssignStat("ydsl",$passing[$i + 7]);
  $people[$name]->AssignStat("td",$passing[$i + 8]);
  $people[$name]->AssignStat("int",$passing[$i + 9]);
 }
 
 
 print_r($people);
 
 ?>
 [/code]

You access each player by

[code=php]
 $players["playername"];
 [/code]

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