Image Upload

Im doing an image upload, and I have this information:

The upload file page (phpfile.php)

[code]
<form name=”form1″ method=”post” action=”phpupload.php” enctype=”multipart/form-data”>
<input type=”file” name=”imagefile”>
<br>
<input type=”submit” name=”Submit” value=”Submit”>
</form>
[/code]

and

this page to supposedly show the file (phpupload.php)

[code]
<?php
if(isset( $Submit ))
{
//If the Submitbutton was pressed do:

if ($_FILES[‘imagefile’][‘type’] == “image/gif”)
{
copy ($_FILES[‘imagefile’][‘tmp_name’], “files/”.$_FILES[‘imagefile’][‘name’])
or die (“Could not copy”);

echo “”;
echo “Name: “.$_FILES[‘imagefile’][‘name’].””;
echo “Size: “.$_FILES[‘imagefile’][‘size’].””;
echo “Type: “.$_FILES[‘imagefile’][‘type’].””;
echo “Copy Done….”;
}

else
{
echo “<br><br>”;
echo “Could Not Copy, Wrong Filetype (“.$_FILES[‘imagefile’][‘name’].”)<br>”;
}
}
?>
[/code]

I dont know if this is coded right or not, because the information isn’t showing up on the page after it supposedly uploads.

I tried doing this with a text file, and it works fine, I can see the text within the file.

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