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reg ex help …

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Apr 04.2003

I want to split a string of numbers into an array of four characters each…
This is what i did:

<SCRIPT LANGUAGE=”JavaScript”>
<!–
str=”49384389749848748234343343433″
re = new RegExp(“[0-9]{1,4}”, “g”);
alert(str.split(re))
//–>
</SCRIPT>

returns nothing ?

Any feedback ???

to post a comment
JavaScript

7 Comments(s) ↴

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@JonaApr 04.2003 — You don't use split(), you use this:

re.exec(str);
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@aapunauthorApr 04.2003 — Jona,

thank you for the lead.


I tried this as per your suggestion.

alert(str.split(re))

It shows only the first four characters. I dont get the entire array. Am i missing something in my reg ex ??? Do i need to mention a star somewhere. How do i make him split after the first four characters ?? :rolleyes:
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@JonaApr 04.2003 — You are using split(), you should be using:

alert(re.exec(str));
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@aapunauthorApr 04.2003 — oops my bad, typo !!

I tried this... it displays only the first 4 chars

<!--

str="49384389749848748"

re = new RegExp("[0-9]{1,4}", "g");

//alert(str.split(re))

alert(re.exec(str))

//-->
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@soccer362001Apr 05.2003 — This part: {1,4} is what makes it only allowed to go through the first 4 characters. Take that out and see what happens.

P.S. This is Jona (not at home).
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@jeffmottApr 05.2003 — [size=2]var str = "49384389749848748234343343433";
var re = new RegExp("\d{1,4}", "g");
alert(str.match(re));[/size]
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@NedalsApr 05.2003 — Bit long-winded, but it works.

myRe=/d{4}/g;

str="49384389749848748";

strlen = Math.ceil(str.length/4)

var Ary = new Array();

for (i=0; i<strlen; i++) {

Ary[i] = myRe.exec(str);

alert(Ary[i]);

}



There must be a better way!! ?



jeff post appeared after I posted. I knew there was a better way ?
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