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Problem with doing some javascript math on the fly

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Jun 30.2005

I am doing some calculations on the fly for my client, but the javascript keeps returning a nan when I put my numbers into the fields. On the front end I am using 2 labels (one they can not change, and other being the total cost. then there are 3 textboxes that can be manipulated to equate the correct total.

Any help would be greatly appreciated. BTY, programming in vb.net with javascript.

[CODE]function doCalcVendorFees(){

var el1=document.getElementById(“lblBaseFee”).innerHTML;
var el2=document.getElementById(“txtCopyFee”);
var el3=document.getElementById(“txtCertificationFee”);
var el4=document.getElementById(“txtOtherFee”);

var FeeTotal = parseFloat(el1.value + el2.value + el3.value + el4.value);
document.getElementById(“lblFeeTotal”).innerHTML = FeeTotal;

}[/CODE]

Thank you in advance.

CommDown

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JavaScript

5 Comments(s) ↴

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@vwphillipsJun 30.2005 — el1.value + el2.value + el3.value + el4.value

these are all strings

each one needs to be changed to a numer before adding
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@CommDownauthorJul 01.2005 — OK, I have made sure that they are all numbers now, but I am still getting NaN, maybe I am missing something. JavaScript, by far, is not my strong point. Thanks for any help!

[CODE]function doCalcVendorFees(){

var el1 = document.getElementById("lblBaseFee").innerHTML;
var el2 = document.getElementById("txtCopyFee").value;
var el3 = document.getElementById("txtCertificationFee").value;
var el4 = document.getElementById("txtOtherFee").value;
var FeeTotal = 0.0;

if (el1.length < 1) {
FeeTotal += parseFloat(el1);
}
if (el2.length < 1) {
FeeTotal += parseFloat(el2);
}
if (el3.length < 1) {
FeeTotal += parseFloat(el3);
}
if (el4.length < 1) {
FeeTotal += parseFloat(el4);
}

alert(FeeTotal)
document.getElementById("lblFeeTotal").innerHTML = FeeTotal.toString();

}[/CODE]

I added the if statements to make sure that if the fields are empty, it calculates accordingly.

Thanks

CommDown
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@ccoderJul 01.2005 — The only time you increment FeeTotal is when a field is empty (.length < 1). Change the test to .length > 0.
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@CommDownauthorJul 01.2005 — Thank you, that was a simple overlook... one last question, if I have half dollar amounts (ie. 4.50) it drops the last zero so it would be 4.5 how can I get that to carry the two decimal points?
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@ccoderJul 01.2005 — Here is some code that I found somewhere (I should probably make a note of these things so I can give credit to the proper sources).
<i>
</i> function format(expr, decplaces)
{
// raise incoming value by power of 10 times the
// number of decimal places; round to an integer; convert to string
var str = "" + Math.round(eval(expr) * Math.pow(10, decplaces))

<i> </i> // pad small value strings with zeros to the left of rounded number
<i> </i> while (str.length &lt;= decplaces)
<i> </i> str = "0" + str

<i> </i> // establish location of decimal point
<i> </i> var decpoint = str.length - decplaces

<i> </i> // assemble final result from: (a) the string up to the position of
<i> </i> // the decimal point; (b) the decimal point; and (c) the balance
<i> </i> // of the string. Return finished product.

<i> </i> return str.substring(0, decpoint) + "." + str.substring(decpoint, str.length);

<i> </i> } // end of format
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