function to find the contents of a dir

@bokehMay 10.2005 — #

[code=php]
 <?php
 
 $dir = '/path/to/image/directory/from/root/';
 
 //get directory contents
 $contents = array();
 
 $dir = opendir($_SERVER['DOCUMENT_ROOT'] . $dir);
 
 while (false !== ($file = readdir($dir))) {
 $contents[] = $file;
 }
 closedir($dir);
 
 
 
 // Print file names
 foreach($contents as $file){
 if(($file != '.') and ($file != '..')){
 print ($file . '<br>');
 }
 }
 
 ?>
 [/code]

Or the following to display them

[code=php]
 <?php
 
 $dir = '/path/to/image/directory/from/root/';
 
 //get directory contents
 $contents = array();
 
 $dir = opendir($_SERVER['DOCUMENT_ROOT'] . $dir);
 
 while (false !== ($file = readdir($dir))) {
 $contents[] = $file;
 }
 closedir($dir);
 
 //get only jpeg contents
 $jpeg_contents = array();
 
 foreach($contents as $file){
 if (eregi('.jpg{1}$', $file)){
 $jpeg_contents[] = $file;
 }
 }
 
 // display images
 foreach($jpeg_contents as $file){
 print ('<img src="/http/path/to/directory/' . $file . '"><br>' . "n");
 }
 
 ?> 
 [/code]

Edit: You could scale all that down to something like the following:

[code=php]
 <?php
 $dir = '/path/to/image/directory/from/root/';
 
 $dir = opendir($_SERVER['DOCUMENT_ROOT'] . $dir);
 
 while (false !== ($file = readdir($dir))) {
 if (eregi('.jpg{1}$', $file)){
 print ('<img src="/http/path/to/image/directory/' . $file . '"><br>' . "n");
 }
 }
 closedir($dir);
 ?>
 [/code]

function to find the contents of a dir

3 Comments(s) _↴

Also in #PHP _↴

Success!

Social

Version

function to find the contents of a dir

3 Comments(s) ↴

Also in #PHP ↴

Success!

The web is an endless sea of information. Don't miss the boat... Subscribe!

Social

Version

3 Comments(s) _↴

Also in #PHP _↴