@AdamBrillMar 14.2003 — #Since PHP only runs once when the page loads, you can't get the information directly into a PHP variable. You have to make a hidden input field and get the data out of that. Or, since it looks like you are using a external file, you could just read the file and get the information that way. Something like this should work:[code=php]<?PHP $filename = "http://www.leaguez.com/extern/?clan=7333&ladder=8&type=1"; $fp = file($filename); if($fp){ $content = ""; $x=0; while($fp[$x]){ $content.=$fp[$x]; $x++; } echo $content; } ?>[/code]The variable $content has the data out of the file. Let me know if you need any more help. ?