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join variable function ${‘text’. $i}

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Jan 13.2005

Hi, in my old website I found this function that is used to create new variable based on string and variable….

[code=php]
$i=”1″;
$a=${‘text’. $i};

echo $a; //returns text1

[/code]

This function is used fot DB cycling…. exept it doesnt work for some reason on a new server… so can somebody explane me why isnt it working and maybe give me a link to documentation?

Thanks!

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PHP

9 Comments(s) ↴

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@sciguyryanJan 13.2005 — I'm not exactly wshure what your doing but why don't you try and use [url=http://www.php.net/eval]eval()[/url]?


If you want the link to the PHP documentation then have a look in my signature.


RyanJ
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@ShrineDesignsJan 13.2005 — try:[code=php]<?php
$i = 1;
eval("$text$i = 'foobar';");
echo $text1;
?>[/code]
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@NogDogJan 13.2005 — [i]Originally posted by ShrineDesigns [/i]

[B]try:[code=php]<?php
$i = 1;
eval("$text$i = 'foobar';");
echo $text1;
?>[/code] [/B][/QUOTE]
Better yet, try:
[code=php]
$i = 1;
$text[$i] = 'foobar';
echo $text[$i];
[/code]
?
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@alexusauthorJan 13.2005 — Ok, I guess I'll have to use eval();

but then how can I properly cycle this to ptint txt$i:

[code=php]
$txt1="1";
$txt2="2";
$txt3="3";
$txt4="4";
$txt5="5";
$txt6="6";
$txt7="7";

while(?????){
$str = 'txt$i';
eval("$str = "$str";");
echo $str;
$i++;
}
[/code]
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@pyroJan 13.2005 — What exactly are you trying to do here? From the example you gave, using an array would make a heck of a lot more sense, as you could just iterate through the array to echo out the values.
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@NogDogJan 13.2005 — [code=php]
# assume there are variables $text1 - $text99
for($i=1;$i<=99;$i++)
{
eval("\$text$i = \"foobar\";");
}
[/code]
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@alexusauthorJan 13.2005 — what if I dont what is the number of $txt$i (that is why i needed it) yhe numbet may vary ,,,
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@NogDogJan 13.2005 — [i]Originally posted by alexus [/i]

[B]what if I dont what is the number of $txt$i (that is why i needed it) yhe numbet may vary ,,, [/B][/QUOTE]
[code=php]
$ix = 1;
while(TRUE) ### DANGER, WILL ROBINSON!!!!!
{
eval("if(!isset(\$text$ix)) { break ; }");
eval("\$text$ix = \"foobar\";");
$ix++;
}
[/code]
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@alexusauthorJan 16.2005 — NogDog, your example returns an error...

Well any way I got my function to work the way I need it.

Here is the code:
[code=php]
$txt1='1';
$txt2='2';
$txt3='3';
$txt4='4';
$txt5='5';
$txt6='6';
$txt7='7';

$i=1;
while( isset(${'txt' .$i})){
echo ${'txt' .$i};
$i++;
}
[/code]

This will return: "1234567"

I thin this function is way more easy to use rather then eval()
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