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MySQL Question

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Nov 14.2004

Alright, I am not quite sure how to do this, hopefully I can explain it well enough so someone can help me. It OUGHT to be simple, I just cant seem to figure it out.

[CODE]$query1 = “SELECT id, name FROM dyn”;
$results1 = mysql_query($query1) or die(mysql_error());

while ($dyn = mysql_fetch_assoc($results1)) {
foreach ($dyn as $a) {
echo $a;
echo “<br />”;
}
}[/CODE]

That is straightforward. There are 11 occurrences that this query outputs. And I only want one of them, particularly I want the one where $dyn[‘id’] = $ahop[‘id’] (another variable I have on this page.

What would be the best way to do this?

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PHP

2 Comments(s) ↴

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@ShmohelauthorNov 14.2004 — Of course, I spend 45 minutes trying to figure it out, I resort to posting on the boards, and 2 minutes later it occurs to me.

For anyone else, this is what I did:

<i>
</i>$dyn = mysql_fetch_assoc($results1);
if ($dyn['id'] = $ahop['id']) {
foreach ($dyn as $a) {
echo $a;
echo "&lt;br /&gt;";
}
}
Copy linkTweet thisAlerts:
@Paul_JrNov 14.2004 — [i]Originally posted by Shmohel [/i]
<i>
</i>$dyn = mysql_fetch_assoc($results1);
if ($dyn['id'] [color=red][b]=[/b][/color] $ahop['id']) {
foreach ($dyn as $a) {
echo $a;
echo "&lt;br /&gt;";
}
}
[/QUOTE]
That should be two equals signs ("=="); = is the assignment operator, whereas == is the comparison operator.
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