How to split string by seperator not in quotation?

@wyx2000Aug 29.2004

Thanks ahead.

I have a regex question, I have string like

userage “please input your age.” %1 %2

I want to split it, so I get four pieces like

userage
“please input your age.”
%1
%2

that means seperate it by space, but not include those spaces in quotation, any suggestion?

Thanks!

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JavaScript

18 Comments(s) _↴

@JonaAug 29.2004 — #[font=trebuchet ms]Split it by the quotes first (".+"), then the remaining string split by whitespace (s+).[/font]

@CharlesAug 29.2004 — #Better yet, don't split it. Just use the regular expression to grab what you want …

[font=monospace]<script type="text/javascript">



</script>[/font]

@JonaAug 29.2004 — #[font=trebuchet ms]Charles, the only concern I'd have then is that perhaps the string is not always exactly the same in all parts.[/font]

@wyx2000authorAug 29.2004 — #Thanks!

Sounds a good solution, I was always looking for one statement to do that.

Just tried it, split userage "please input your age." %1 %2 with ".+", I only get two pieces:

userage

%1 %2

I think what I need is three pieces :

userage

"please input your age."

%1 %2

this way, I know which pieces include quotation and I can continue split others with spaces.

Any idea?

@JonaAug 29.2004 — #[i]Originally posted by wyx2000 [/i]

[B]Thanks!

Sounds a good solution, I was always looking for one statement to do that.

Just tried it, split userage "please input your age." %1 %2 with ".+", I only get two pieces:

userage

%1 %2

I think what I need is three pieces :

userage

"please input your age."

%1 %2

this way, I know which pieces include quotation and I can continue split others with spaces.

Any idea? [/B][/QUOTE]

[font=trebuchet ms]Store the variable with parentheses. [i]"(.+)"[/i]

Charles' method may be more useful for you if you are looking for a relatively similar string each time, though.[/font]

@wyx2000authorAug 29.2004 — #as you said they are not in fixed format. so charles's solution doesn't work for me.

just tried

var re = new RegExp(/"(.+)"/, "g");

var params='userage "please input your age." %1 %2'.split(re);

for(var j = 0; j <params.length; j++){

alert(params[j]);

}

it still only returns two pieces/

@JonaAug 29.2004 — #

<i>
 </i>&lt;script type="text/javascript"&gt;
 var re = /"(.+)"/g;
 var params='userage "please input your age." %1 %2'.split(re);
 
 for(var j = 0; j &lt;params.length; j++){
 alert(params[j]);
 }
 &lt;/script&gt;

@wyx2000authorAug 29.2004 — #hmm, your code doesn't look different from mine. And I just run it, got same results, only two pieces returned

@CharlesAug 29.2004 — #I think we need a lot more information about just what this string is going to look like and just what we're trying to extract.

@JonaAug 29.2004 — #[font=trebuchet ms]Hm, [url=http://209.169.115.234/jona/research/javascript/wyx2000/regex.html]it works for me[/url].[/font]

@JonaAug 29.2004 — #[i]Originally posted by Charles [/i]

[B]I think we need a lot more information about just what this string is going to look like and just what we're trying to extract. [/B][/QUOTE]

[font=trebuchet ms]I second that; we have no clue as to what the possible strings would look like, other than what you showed us. Will they all follow the same format, exactly?[/font]

@wyx2000authorAug 29.2004 — #[i]Originally posted by Jona [/i]

[B][font=trebuchet ms]Hm, [url=http://209.169.115.234/jona/research/javascript/wyx2000/regex.html]it works for me[/url].[/font] [/B][/QUOTE]

strange, I still only get two alerts from the your url

userage and %1, %2

those commands I use to tell one of my js function how to check user input, they will be lines like

hide %1

hide

admin %n{Admin level for this user|3|^{^[0-9]+$|3|7}} %1

so first command take one parameter

second doesn;t need parameter

the third take two parameters, note here that they are a little different from what I asked in my question, take the third as an example, I use %1 to start a parameter, so there are two

%n{Admin level for this user|3|^{^[0-9]+$|3|7}}

%1

%n = integer

%1 = predefined first object

there are other parameters like %s and more... so it is better to split the string by space, but the spaces in bracket, that means spaces in "Admin level for this user|3|^{^[0-9]+$|3|7"} servers other purpose, what I tried to do is slit the string by space, but not include space in bracket.

Is it more clear to you?

@JonaAug 29.2004 — #[font=trebuchet ms][url=http://209.169.115.234/jona/research/javascript/wyx2000/regex.html]Is this better[/url]? The reason it didn't work was because you're using Internet Explorer; it worked in Mozilla Firefox. ? [/font]

@wyx2000authorAug 29.2004 — #[i]Originally posted by Jona [/i]

[B][font=trebuchet ms][url=http://209.169.115.234/jona/research/javascript/wyx2000/regex.html]Is this better[/url]? The reason it didn't work was because you're using Internet Explorer; it worked in Mozilla Firefox. ? [/font] [/B][/QUOTE]

It works, but not quite, I mean it seems the way it tells if it is a quoted string is not so ideal.

It is my fault, I should just ask this at the beginning. I have to do it now, since I still have no clue to get what I want, it is how to split this string

%n{Admin level for this user|3|^{^[0-9]+$|3|7}} %1 %2

to pieces like

%n{Admin level for this user|3|^{^[0-9]+$|3|7}}

%1

%2

really appreciate you guys' help.

@JonaAug 29.2004 — #[font=trebuchet ms]To make it easier on us, use a multicharacter delimiter, instead of a space. E.g.: %n{Admin level for this user|3|^{^[0-9]+$|3|7}_***_%1_***_%2}

That way, you can just split it by _***_, which is likely not to occur in your string.[/font]

@wyx2000authorAug 29.2004 — #[i]Originally posted by Jona [/i]

[B][font=trebuchet ms]To make it easier on us, use a multicharacter delimiter, instead of a space. E.g.: %n{Admin level for this user|3|^{^[0-9]+$|3|7}_***_%1_***_%2}

That way, you can just split it by _***_, which is likely not to occur in your string.[/font] [/B][/QUOTE]

Nice solution,? , you are right, maybe I should just make it work first.

@JonaAug 29.2004 — #[font=trebuchet ms]There's always an alternative when it comes to JavaScript. Well, almost always. ? [/font]

@wyx2000authorAug 29.2004 — #Maybe I always try to find a normal solution(if not best solution), just don't feel comfortable about some quick solution.

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