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Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in on line 28
Line 28 is the
$result2 = mysql_query($sql2, $conn) or die(mysql_error());
if (mysql_num_rows($result2 ==1)) {
The entrie source can be found
Thanks Adam[URL=http://www.webdeveloper.com/forum/showthread.php?s=&postid=227556#post227556]Here
Thanks Adam