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@NogDogDec 13.2021 — #First question: do you really need this, or could it be solved by
If you just want to accept the warning condition, you can suppress it just for that command with the
If you want to make sure your code is forward compatible on the off chance they ever make that an error instead of a warning, you could create a little function for whenever you need it:
Most efficient php array management
I am populating an array with values I read in from the database.
At the same time, I generate an array of unique values e.g. `$deptList[$row[“dept”]]++
Now, this generates a PHP Notice: `PHP Notice: Undefined index: DeptB
Is it more efficient to leave this and hide PHP Notices than it is creating an if statement to handle?
I don’t like errors but, is adding an extra if statement really needed?
Which is more efficient:
Now
`$deptList[$row[“dept”]]++
After
`isset($deptList[$row[“dept”]])?$deptList[$row[“dept”]]++:$deptList[$row[“dept”]]=0
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@NogDogDec 13.2021 — #First question: do you really need this, or could it be solved by count()$deptList[$some_key_or_whatever]count()If you just want to accept the warning condition, you can suppress it just for that command with the
@[code=php]
@$deptList[$row["dept"]]++;
[/code]If you want to make sure your code is forward compatible on the off chance they ever make that an error instead of a warning, you could create a little function for whenever you need it:
[code=php]
function increment(&$foo) { // note "&" to pass argument by reference
$foo = is_null($foo) ? 1 : ++$foo; // need to use the "prefix" version of ++
}
// usage:
increment($deptList[$row["dept"]]);
echo $deptList[$row["dept"]]; // 1
[/code]