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1 becomes 0 and 0 becomes 1

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Jul 22.2021

Hi,
I need to print numbers from 1 to 100 without using numbers.
So far I got to here, where I am trying to get numbers 1 and 0 but the problem is that one becomes 0 and zero becomes 1 after I use “–“

“`
let a = “a”;
let one = a.length;
let zero = one–;

console.log(`One is ${one} and zero is ${zero}`)
“`

Can you tell me why this is happening?

to post a comment
JavaScript

16 Comments(s) ↴

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@tracknutJul 22.2021 — You're misunderstanding what this does:

let zero = one--;
[/quote]
*post* decrement does the assignment into zero and *afterwards* it decrements one. It is equivalent to:

let zero = one;

--one;
[/quote]
*pre* decrement would first decrement one, then assign it to zero, leaving you with both zero and one = 0. Neither of those is likely what you want :) but rather something like this?

let zero = one;

--zero;
[/quote]
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@NogDogJul 22.2021 — > @RaulRogojan#1634521 I need to print numbers from 1 to 100 without using numbers.

This is where you lost me. ;)
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@codewitchJul 22.2021 — @RaulRogojan#1634521

I need to print numbers from 1 to 100 without using numbers.

<i>
</i>&lt;!DOCTYPE html&gt;
&lt;html&gt;
&lt;body&gt;

&lt;?php

$s="";
$s=$s.'a'; echo strlen($s).'&lt;br /&gt;';
$s=$s.'a'; echo strlen($s).'&lt;br /&gt;';
$s=$s.'a'; echo strlen($s).'&lt;br /&gt;';
$s=$s.'a'; echo strlen($s).'&lt;br /&gt;';
$s=$s.'a'; echo strlen($s).'&lt;br /&gt;';
$s=$s.'a'; echo strlen($s).'&lt;br /&gt;';
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$s=$s.'a'; echo strlen($s).'&lt;br /&gt;';
$s=$s.'a'; echo strlen($s).'&lt;br /&gt;';
$s=$s.'a'; echo strlen($s).'&lt;br /&gt;';

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$s=$s.'a'; echo strlen($s).'&lt;br /&gt;';
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$s=$s.'a'; echo strlen($s).'&lt;br /&gt;';

?&gt;

&lt;/body&gt;
&lt;/html&gt;


Explanation: you start with an empty string, then you just increase length of that string by one char string and you print its length. You repeat 100x.
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@codyhillauthorJul 22.2021 — @NogDog#1634558 A friend of mine received this question on an interview so I give it a try.
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@codyhillauthorJul 22.2021 — @codewitch#1634560 I think this is a better solution. :D
``<i>
</i>const one = "a".length;
const ten = "aaaaaaaaaa".length;
const oneHundred = ten * ten;

for(let i = one; i &lt;= oneHundred; i++) {
console.log(i);
};<i>
</i>``
But I am still interested why what was I trying to do was not working
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@codyhillauthorJul 22.2021 — @tracknut#1634554 if you console log that it says zero is = to 1. Which was the confusing part. I figure why one became = 0 but I did not understand why zero became = 1
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@codyhillauthorJul 22.2021 — @tracknut#1634554 I have made this change and it works now.
``<i>
</i>let a = "a";
let one = a.length;
let zero = one - one;

console.log(One is ${one} and zero is ${zero})<i>
</i>`</CODE>
The reason I needed 0 is because I know "d".charCodAt = 100 but I need to write it this way<br/>
<C>const hundred = "d".chatCodeAt(0);`

There is a need for a 0 witch by problem requirement I am not allowed to use numbers.

But I still don't understeand why zero = one-- became 1.
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@codewitchJul 22.2021 — @RaulRogojan#1634563

Indeed, your solution is better.

Here is php version:

<i>
</i>&lt;!DOCTYPE html&gt;
&lt;html&gt;
&lt;body&gt;

&lt;?php

$one=strlen("a");
$ten=strlen("aaaaaaaaaa");
for($i=$one;$i&lt;=$ten*$ten;$i++){
echo $i.'&lt;br /&gt;';
}

?&gt;

&lt;/body&gt;
&lt;/html&gt;
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@codyhillauthorJul 22.2021 — @codewitch#1634566 Awesome!
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@tracknutJul 22.2021 — @RaulRogojan#1634565


But I still don't understeand why zero = one-- became 1.
[/quote]

because this line:

let zero = one--;
[/quote]
First assigns "zero" to the value of "one" (which is 1), and then *after that assignment* it decrements the value of "one"
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@NogDogJul 22.2021 — @codewitch#1634566 PHP golf! . . .
[code=php]
<pre><?php foreach(range(true, ord('d')) as $i) echo "$in"; ?></pre>
[/code]
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@codewitchJul 22.2021 — NogDog has a one line solution. Congratulations.

BTW What does it mean php golf?
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@NogDogJul 22.2021 — And a few less "strokes":
[code=php]
<pre><?php echo implode("n", range(true, ord('d'))); ?></pre>
[/code]
;)
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@codewitchJul 22.2021 — Here is my attempt:

<i>
</i>&lt;?php for($i=ord(false);$i&lt;ord("d");$i++){echo ($i+true).'&lt;br&gt;';} ?&gt;


It is one character shorter!

EDIT: Ok, NodDog, you have won!

Your: &lt;pre&gt;&lt;?php echo implode("n", range(true, ord("d"))); ?&gt;&lt;/pre&gt; has a length of 62

Mine: &lt;?php for($i=ord(false);$i&lt;ord("d");$i++){echo ($i+true).'&lt;br&gt;';} ?&gt; has a length of 68

Your code is shorter..
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@NogDogJul 22.2021 — > @codewitch#1634572 BTW What does it mean php golf?

Used to be a thing (maybe still is) to have contests of sorts to see who could write the smallest amount of code to accomplish some task in a particular programming language. (I.e., in golf, the goal is to complete the course with the fewest number of strokes.)

Note that while it can be an interesting exercise, for the vast majority of applications your emphasis should be on code readability and maintainability -- number of characters is highly unimportant these days (as compared to decades ago when it could affect performance).
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@codewitchJul 22.2021 — Thank you for the explanation.
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