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sunday day

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Jun 16.2004

hi,

can anyone help me…

how to get the sunday day for the whole next month…..?

for example:
next month is july..then how to get the day of the sunday day for the whole july?

thanks…..

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PHP

2 Comments(s) ↴

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@crh3675Jun 16.2004 — <i>
</i>&lt;script type="text/javascript"&gt;
var d=new Date();
var sundays=Array();

var month=3;
var year=2004;

d.setMonth(month-1); // Javascript starts months at 0
d.setYear(year);

for(i=1;i&lt;=31;i++){
var m=d.getMonth();
if(m==(month-1)){
d.setDate(i);
if(d.getDay()==0){
sundays[sundays.length]=month+"/"+i+"/"+year;
}
}else{
break;
}
}

for(i=0;i&lt;sundays.length;i++){
alert(sundays[i]);
}
&lt;/script&gt;


Oops. That's javascript. But you can use the same concept for PHP.

<i>
</i>&lt;?
$date="4/1/2004";

$timestamp=strtotime($date);
$m=date("m",$timestamp);
$sundays=Array();

for($i=1;$i&lt;=31;$i++){

<i> </i>$temptime=mktime(0,0,0,date("m",$timestamp),$i,date("Y",$timestamp));
<i> </i>if($m==date("m",$temptime)){
<i> </i> if(date("w",$temptime)==0){
<i> </i> $sundays[count($sundays)]=date("m/d/Y",$temptime);
<i> </i> }
<i> </i>}else{
<i> </i> break;
<i> </i>}
}

for($i=0;$i&lt;count($sundays);$i++){
echo $sundays[$i]."&lt;br/&gt;";
}
?&gt;


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@r3sannauthorJun 16.2004 — thank u

the ultimate web nerd....


thanks a lot ..

r3sann
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