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mysql query question

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Jun 02.2004

<?php
$conn = mysql_connect(“localhost”,””,””);
$db = mysql_select_db(“dbzwars”);
$sql = ‘SELECT * FROM users’;
$result = mysql_query($sql);
print $result;
?>

im trying to print all the information in the database
with that it prints
Resource id #2

does anyone have a clue what im doing wrong

to post a comment
PHP

3 Comments(s) ↴

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@pyroJun 02.2004 — You'll need to loop through the results. Something like this:

[code=php]<?php
$conn = mysql_connect("localhost","","");
$db = mysql_select_db("dbzwars");
$sql = 'SELECT * FROM users;';
$result = mysql_query($sql);
while ($row = mysql_fetch_array($result)) {
echo $row['name'];
}
?>[/code]
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@daveyauthorJun 02.2004 — with that code nothing appears
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@Paul_JrJun 02.2004 — [i]Originally posted by davey [/i]

[B]with that code nothing appears [/B][/QUOTE]
Unless you have a field in your table called &#8220;name&#8221; then no, it will not show anything. You have to subsitute [font=courier]$row["name"][/font] with the names of the fields whose values you wish to display on the page.
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