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PHP Echo not displaying

I have this in my image script, I know you you when you have ” in php. How can I make this show thru as well.

[code=php]
Problem with:

onMouseOver=/”(window.status=’BUTTON NAME’); return true” onMouseOut=”(window.status=”); return true”

Link:

echo ” <a class=”barmenu” href=”https://www.uwccr.org/intranet”><font color=”FFE3BA”>INTRANET</font></a>&nbsp;|&nbsp;n”;

[/code]

This above is when they rollover the link, it displays the name in the status bar, it works fine in .html, but when I echo it in php, it won’t come up, do I have the in the wrong places?

DB

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PHP

4 Comments(s)

Copy linkTweet thisAlerts:
@DariaMay 20.2004 — I don't know much, but right away I see your very first quotation marks " have a forward-slash / instead of back-slash

If it's not solving the problem, someone who actually knows php I'm sure will help.
Copy linkTweet thisAlerts:
@d_brandusaauthorMay 20.2004 — I just did that to show you I have a slash there, this webforum kept deleting it.
Copy linkTweet thisAlerts:
@MstrBobMay 20.2004 — [code=php]
echo("<a class="barmenu" href="https://www.uwccr.org/intranet" onMouseOver="window.status='BUTTON NAME'; return true;" onMouseOut="(window.status=''); return true;"><font color="FFE3BA">INTRANET</font></a>&nbsp;|&nbsp;n");
[/code]


That above code seems to work on my server, see if it helps any.
Copy linkTweet thisAlerts:
@DariaMay 20.2004 — If missing in front of "barmenu would be placed it should work fine
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