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I have this in my image script, I know you you when you have ” in php. How can I make this show thru as well.
[code=php]
Problem with:
onMouseOver=/”(window.status=’BUTTON NAME’); return true” onMouseOut=”(window.status=”); return true”
Link:
echo ” <a class=”barmenu” href=”https://www.uwccr.org/intranet”><font color=”FFE3BA”>INTRANET</font></a> | n”;
This above is when they rollover the link, it displays the name in the status bar, it works fine in .html, but when I echo it in php, it won’t come up, do I have the in the wrong places?
DB