Menu
Community /Pin to ProfileBookmark
@NogDogDec 02.2015 — #You have to echo whatever it is you assigned it to:
@NogDogDec 04.2015 — #In case this has anything to do with it, remember that variables defined within a function are scoped locally only to that function. If you need access to them outside of that function, then the function needs to return it so that you can assign it to a variable...
(There are some other ways around it, such as passing variables by reference to the function or using the "global" keyword in the function; but that can get a bit messy, and the latter option of using "global" is highly frowned upon as it makes code difficult to debug and/or to re-use.)
simple question from a newbie
Hello,
i declare a variable some place in a php file as follows
$data[‘name’] $this->language->get(‘name’);
and just below i try to show it
echo $name ;
i get this error : undefined variable work
i change the declaration as follows
$name =$this->language->get(‘name’);
i works .
But code has to work with $data keyword .. (i try to modify a framework called Opencart)
what is that i do wrong with $data ??
Thank you..
Sign in
to post a comment7 Comments(s) ↴
0
@NogDogDec 02.2015 — #You have to echo whatever it is you assigned it to:[code=php]
$data['name'] = $this->language->get('name');
echo $data['name'] ;
[/code]0
@NogDogDec 04.2015 — #In case this has anything to do with it, remember that variables defined within a function are scoped locally only to that function. If you need access to them outside of that function, then the function needs to return it so that you can assign it to a variable...[code=php]
$myVar = someFunction();
[/code](There are some other ways around it, such as passing variables by reference to the function or using the "global" keyword in the function; but that can get a bit messy, and the latter option of using "global" is highly frowned upon as it makes code difficult to debug and/or to re-use.)