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@NogDogJun 18.2015 — #If this is all PHP code, then you have PHP inside of PHP:
What you want to do instead is use concatenation, or exit out of PHP mode then back in, e.g.:
Adding a logout link to my footer menu
Hi all
I should start by saying I am a complete coding novice!
I currently have this code in my functions.php to control my footer menu:
[CODE]add_filter(‘omega_footer_insert’, ‘my_omega_footer_insert’, 11);
function my_omega_footer_insert( $settings ) {
$year = date( ‘Y’ );
$siteurl = get_bloginfo( ‘url’ );
$sitename = get_bloginfo( ‘name’ );
return “<a href=’http://bibliophone.com/about/’>About</af=’http://bibliophone.com/terms-of-use/’>Terms</a> | <a href=’http://bibliophone.com/privacy-policy/’>Privacy</a><br>© <a href=’$siteurl’>$sitename</a> $year</p>”;
}
That code works fine and appears exactly as I want it to, but I want to add a logout link to this, which displays ONLY when a user is registered and logged in. I have this code:
[CODE]if ( is_user_logged_in() ) {
echo ‘ | <a href=”<?php echo wp_logout_url( get_permalink() ); ?>” title=”Logout”>Logout</a>’;
}
..but I’m not having much luck with it because I don’t know for certain that it’s correct, and secondly I’m not sure where it should be placed within the first bit of code above. Can anyone help please?
Thank you!
Paul
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@NogDogJun 18.2015 — #If this is all PHP code, then you have PHP inside of PHP:[code=php]
<?php
if ( is_user_logged_in() ) {
echo ' | <a href="<?php echo wp_logout_url( get_permalink() ); ?>" title="Logout">Logout</a>';
}
[/code]What you want to do instead is use concatenation, or exit out of PHP mode then back in, e.g.:
[code=php]
<?php
// ...start of script, then...
if ( is_user_logged_in() ) {
?>
| <a href="<?php echo wp_logout_url( get_permalink() ); ?>" title="Logout">Logout</a>
<?php
}
// rest of script...
[/code]