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Ternary operator

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Dec 23.2013

Hi

Can someone help me to translate this code:

[CODE]

return ( ( ayr[7] >> ch | tons >> ch )
& ( ayr[7] >> ch+3 | noiv )
& 1 ) * amp[ ayr[8+ch] & 0x10
? envv
: ayr[8+ch] & 0x0f ];
[/CODE]

in to IF ELSE expression?

Thank´s

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JavaScript

9 Comments(s) ↴

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@JMRKERDec 23.2013 — Can you expand on what is supposed to do?

Also, the AND logical comparison is && not a single & character.

And the logical OR is || not | only.

Is your >> supposed to be some sort of right shift operation?

?
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@tracknutDec 23.2013 — Not that it's any easier to read:
<i>
</i>if (ayr[8+ch] &amp; 0x10)
return (( ( ayr[7] &gt;&gt; ch | tons &gt;&gt; ch )
&amp; ( ayr[7] &gt;&gt; ch+3 | noiv )
&amp; 1 ) * amp[envv];
else
return ( ( ayr[7] &gt;&gt; ch | tons &gt;&gt; ch )
&amp; ( ayr[7] &gt;&gt; ch+3 | noiv )
&amp; 1 ) * amp[ayr[8+ch] &amp; 0x0f];


JRMKR, those are all bitwise and's and or's and shifts.
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@JMRKERDec 23.2013 — Not that it's any easier to read:
<i>
</i>if (ayr[8+ch] &amp; 0x10)
return (( ( ayr[7] &gt;&gt; ch | tons &gt;&gt; ch )
&amp; ( ayr[7] &gt;&gt; ch+3 | noiv )
&amp; 1 ) * amp[envv];
else
return ( ( ayr[7] &gt;&gt; ch | tons &gt;&gt; ch )
&amp; ( ayr[7] &gt;&gt; ch+3 | noiv )
&amp; 1 ) * amp[ayr[8+ch] &amp; 0x0f];


JRMKR, those are all bitwise and's and or's and shifts.[/QUOTE]

That was my point. It was not syntax correct.

Still does not make it any easier to decipher without some comments.

I would think 2 weeks away from the code will not make it any easier to decipher than a 6 month hiatus.
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@tracknutDec 23.2013 — I'm missing the part that's not syntactically correct, but certainly agree it's a nightmare to decipher... ?
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@JMRKERDec 24.2013 — I'm missing the part that's not syntactically correct, but certainly agree it's a nightmare to decipher... ?[/QUOTE]

I'm referring to the original post.

Note also that '&' alone is supposed to do what in your post?
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@JRobertoauthorDec 24.2013 — [CODE]
function cstep(ch) {
if( ++ayr[ch+16] >= (ayr[ch<<1] | ayr[1|ch<<1]<<8) )
ayr[ch+16]= 0,
tons^= 1 << ch;
return ( ( ayr[7] >> ch | tons >> ch )
& ( ayr[7] >> ch+3 | noiv )
& 1 ) * amp[ ayr[8+ch] & 0x10
? envv
: ayr[8+ch] & 0x0f ];
}
[/CODE]

This is the complete function that i'm translating to Purebasic syntax.

The first part is not so hard to undesrtand, but i'm very confusing about the 'return ' part. With IF ELSE statements is more easy to understand.

Mostly are bitwise operations.
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@tracknutDec 24.2013 — I'm referring to the original post.

Note also that '&' alone is supposed to do what in your post?[/QUOTE]

Whether the OP or the one I provides, here's an English version for this:
<i>
</i> return (( ( ayr[7] &gt;&gt; ch | tons &gt;&gt; ch )
&amp; ( ayr[7] &gt;&gt; ch+3 | noiv )
&amp; 1 ) * amp[envv];


"take the value of (( ayr[7] >> ch | tons >> ch) and bitwise and it with (ayr[7] >> ch+3 | noiv ) and bitwise and the result with 1 (i.e. get the value of the low order bit). Multiply the result by amp[envv], and return that value. So the returned value will either be zero or amp[envv], depending on the low order bit of the result of all the shifting, or'ing and and'ing"

...and that's only the first half of it ?
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@JRobertoauthorDec 24.2013 — @tracknut

I will try your code.

Thank you!
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