php check box

hi, Im rookie in php checkbox trying to understand how this works.
I create five squares boxes and each box has value number 1 to five
using this code

[CODE]<div class=”sidebar1″>
<ul class=”nav”>
<li><a href=”#”>Link one</a></li>
<li><a href=”#”>Link two</a></li>
<li><a href=”#”>Link three</a></li>
<li><a href=”#”>Link four</a></li>
</ul>[/CODE]

and then i created five check box and each each box has same number assign to the square box number

[CODE]<form action=”” method=”get”><input name=”one” type=”checkbox” value=”1″ />

one<br />
<input name=”two” type=”checkbox” id =”box_two” value=”1″ />
two<br />
<input name=”three” type=”checkbox” id =”box_three” value=”1″ />
three<br />
<input name=”four” type=”checkbox” id =”box_four” value=”1″ />
three<br />
<input name=”five” type=”checkbox” id =”box_five” value=”1″ />
three<br />

</form>[/CODE]

and then if check box is checked set value to one, if not check then set value to zero and update into the database…
here what i wrote..

[CODE]<?php
$box_one = “1”;
$box_two = “1”;
$box_three = “1”;
$box_four = “1”;
$box_five = “1”;

if($box_box1 == 1) { $set_checked = ” 1″;}
else{$set_checked = “0”; }

if($box_two == 1) { $set_checked = ” 1″;}
else{$set_checked = “0”; }

if($box_three == 1) { $set_checked = ” 1″;}
else{$set_checked = “0”; }

if($box_four == 1) { $set_checked = ” 1″;}
else{$set_checked = “0”; }

if($box_five == 1) { $set_checked = ” 1″;}
else{$set_checked = “0”; }

?>[/CODE]

So how can i write the code if any field in database set value 1 in database then display the box, if any field in database set value 0 and not to display box using css or jquery.

how can i write that code!

AM

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