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@NogDogSep 19.2012 — #See the manual page for [url=http://php.net/end]end[/url] (), and notice in the description section that the array argument is passed by reference (indicated by the "&"). In your code you are passing the result of explode(), which while it is an array (assuming it succeeds), there is no variable to pass as a reference. Therefore, you need an intermediate step to create an array variable (and ideally should verify it is, in fact, a successful assignment before assuming it's okay):
Strict Standards: Only variables should be passed by reference in
It is strange error (first time I’ve evern seen this kind of notice)
so i’ve looked over internet and i’ve found nothing so far…
here is the code that is causing it:
[code]function mkthumb($src, $Twidth) {
$name = basename(strtolower($src));
$F = end(explode(“.”, $name));
if($F == “jpg” OR $F == “jpeg”) {
$img = imagecreatefromjpeg($src);
}
else if($F == “png”) {
$img = imagecreatefrompng($src);
} else {
$img = imagecreatefromgif($src);
}
at the line $F = end (explode….
seems to be the problem
So any suggestions?
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@NogDogSep 19.2012 — #See the manual page for [code=php]
$name = basename(strtolower($src));
$exploded = explode(".", $name);
if($exploded === false) { throw new Exception("Oops!"); } // or whatever you want to do
$F = end(exploded));
[/code]