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Fatal error: Call to a member function bindParam() on a non-object in

Hello,

I got the error as in my title and I cant find the problem?

Here is the code of my class:

[code=php] public function GetPostcode($type, $postcode=NULL, $huisnr=NULL)
{
switch($type)
{
case “4XY”:
$sql = “SELECT wijkcode, rd_x, rd_y, lat, lon FROM `postcode`.`4XY`”;
break;
case “5XY”:
$sql = “SELECT wijkcode, letter, rd_x, rd_y, lat, lon FROM `postcode`.`5XY`”;
break;
case “6XY”:
$sql = “SELECT wijkcode, lettercombinatie, rd_x, rd_y, lat, lon FROM `postcode`.`6XY`”;
break;
case “HuisnummerXY”:
$sql = “SELECT nummeraanduidingid, wijkcode, lettercombinatie, huisnr, huisnr_toevoeging, rd_x, rd_y, lat, lon FROM `postcode`.`huisnummerXY`”;
break;
}
if(!empty($postcode))
{
switch($type)
{
case “4XY”:
$sql .= ” WHERE wijkcode=:postcode”;
break;
case “5XY”:
$sql .= ” WHERE wijkcode=:postcode AND letter=:lettercomb”;
break;
case “6XY”:
$sql .= ” WHERE wijkcode=:postcode AND lettercombinatie=:lettercomb”;
break;
case “HuisnummerXY”:
$sql .= ” WHERE wijkcode=:postcode AND lettercombinatie=:lettercomb AND huisnr=:huisnr”;
break;
}
}
try
{
$stmt = $this->db->prepare($sql);
if(!empty($postcode))
{
$stmt->bindParam(“:postcode”, substr($postcode, 0, 4), PDO::PARAM_INT);
switch($type)
{
case “4XY”:
break;
case “5XY”:
$stmt->bindParam(“:lettercomb”, substr($postcode, 4, 1), PDO::PARAM_STR);
break;
case “6XY”:
$stmt->bindParam(“:lettercomb”, substr($postcode, 4, 2), PDO::PARAM_STR);
break;
case “HuisnummerXY”:
$stmt->bindParam(“:lettercomb”, substr($postcode, 4, 2), PDO::PARAM_STR);
$stmt->bindParam(“:huisnr”, trim($huisnr), PDO::PARAM_INT);
break;
}
}
$stmt->execute();
$this->postcodelijst = $stmt->fetchAll(PDO::FETCH_OBJ);
$stmt->closeCursor();

return $this->postcodelijst;
}
catch (Exception $e)
{
die ($e->getMessage());
}
}[/code]

Maybe a fresh look will help me out.

Thanks for any help!?

to post a comment
PHP

4 Comments(s)

Copy linkTweet thisAlerts:
@NogDogJun 26.2012 — [code=php]
$stmt = $this->db->prepare($sql);
if($stmt == false) {
throw new Exception($this->db->errorInfo()."n".$sql);
}
[/code]
Copy linkTweet thisAlerts:
@JoepioooauthorJun 27.2012 — Hey thanks for the reply when I put that piece of code between I get this output:

[CODE]Array SELECT wijkcode, lettercombinatie, rd_x, rd_y, lat, lon FROM postcode.6XY WHERE wijkcode=:postcode AND lettercombinatie=:lettercomb[/CODE]

I still dont have a clue whats wrong... anybody is seeing what is going wrong?
Copy linkTweet thisAlerts:
@JoepioooauthorJun 27.2012 — Solved! User didnt had acces to the database... Very stupid mistake of me?
Copy linkTweet thisAlerts:
@NogDogJun 27.2012 — Just FYI, I forgot that errorInfo() returns an array, not a string. So in case anyone else gets here on a web search:
[code=php]
if($stmt == false) {
$errorText = print_r($this->db->errorInfo(), true);
throw new Exception($errorText."n".$sql);
}[/code]

?
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