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Apr 20.2012

I am trying to get a page to display a total number of members on my forum so have done the following:

created a page containing:

[CODE] <?php
$db_host = ‘localhost’;
$db_user = ‘xx’;
$db_password = ‘xx’;
$db_name = ‘adejones_phpb1’;

mysql_connect($db_host,$db_user,$db_password) or die(mysql_error());
mysql_select_db($db_name) or die(mysql_error());

$result = mysql_query(“SELECT num_users as count FROM phpbb_config”);
echo ‘Total members: ‘.$result[‘count’].'<br>’;
?>[/CODE]

All this does it display “Total members:” with no value afterwards, what am I doing wrong here?

Thanks, Adey

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PHP

2 Comments(s) ↴

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@WyCnetApr 21.2012 — The following snippet can get you closer to your goal:

$result = mysql_query("SELECT num_users as count FROM phpbb_config");
if(mysql_num_rows($result)==0)
echo 'There are no members. '.'&lt;br&gt;';
else{
$data=mysql_fetch_assoc($result);
echo 'Total members: '.$data['count'].'&lt;br&gt;';
}

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@djadejonesauthorApr 21.2012 — Hi WyCnet

That code gave me the following:

Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in /home/adejones/public_html/membercount.php on line 11

There are no members.

I did get a bit closer with the following though:

[CODE]$query = "SELECT config_value FROM phpbb_config WHERE config_name='num_users'";
$result = mysql_query($query);
$array=mysql_fetch_assoc($result);
print_r($array);[/CODE]

This gives me:

Array ( [config_value] => 974 )

Now I just need to get rid of the array config value bit and have just the number.
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