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@NogDogFeb 14.2011 — #I might start with something like this (untested):
You could build upon that by creating an object-oriented class[es] or such, but that should give you plenty to work with.@NogDogFeb 14.2011 — #You don't want an absolute path to the directory, since HTTP requests will be ignorant of the file system. Instead, use a path relative to the script's directory, e.g. "games/Sports/" if the script is in the web root directory, or maybe something like "../games/Sports/" if it's in a separate directory just under the web root.
List files on directory and build the php/html page
Hello there!
I’m making a page with some flash games, but, since in the past will be many games it will be very bored to add all those games one by one on the site. I know that using php we can get the list of the files in the directory and i know that, using this method, i can display all the games on the directory to the visitors page but, i was thinking if you can help me to add an image to each game that correspond with the name of the game. Ex:
In “games” folder we will have games: play1.swf, play2.swf, play3.swf
and, in “images” directory we will have images: play1.jpg, play2.jpg, play3.jpg.
To display the list of the games, can we make a combination of jpg files with swf files? Play1.jpg will be the image of play1.swf game and, when a visitor clicks on the image, will be redirect to a page named ex: playgames.php?play1
Can someone help me on this? It will be a big help for my project.
Thank you very much and waiting for your reply!
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@NogDogFeb 14.2011 — #I might start with something like this (untested):[code=php]
<ul class='video_list'>
<?php
$videoDir = "relative/path/to/videos/";
$imageDir = "relative/path/to/images/";
$videos = glob($videoDir . "*.swf");
foreach($videos as $vid) {
$info = pathinfo($vid);
if(file_exists($imageDir . $info['basename'] . ".jpg")) {
$target = sprintf(
"<img src='%s.jpg' alt='%s'>",
htmlspecialchars($imageDir . $info['filename'] . ".jpg"),
htmlspecialchars($info['basename'])
);
}
else {
$target = htmlspecialchars($info['basename']);
}
printf(
"<li><a href='%s'>%s</a></li>n",
htmlspecialchars($vid),
$target
);
}
?>
</ul>
[/code]You could build upon that by creating an object-oriented class[es] or such, but that should give you plenty to work with.
0
@NogDogFeb 14.2011 — #