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opendir() on an external server

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Aug 18.2010

Hi, I want to be able to check a directory on a different server from where i’m hosting my site.

opendir(‘http://www.example.com/some_directory‘)

Is this even possible? I am currently getting the error:

[function.opendir]: failed to open dir: not implemented in…

I could put a script on the other server to return the value, but i’d prefer to keep it contained.

Thanks in advance.

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PHP

4 Comments(s) ↴

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@NogDogAug 18.2010 — Can you use FTP to the remote server? If so, you could either use the PHP's FTP functions, or possibly opendir with the FTP wrapper ("ftp://" instead of "http://").
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@coldscooterauthorAug 18.2010 — Thanks for the response. I don't think i'm able to use opendir. I will instead use the php ftp functions. Although i worry a little about resource time, if i'm opening up lots of ftp connections all the time.
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@NogDogAug 18.2010 — I'm not sure there's a big difference between opening up a FTP resource or using a http URL wrapper via opendir(). Certainly the latter has few less lines of PHP code to parse and process, but once you get "under the hood", there may not be that much difference. (Or not, I couldn't be sure without doing some metering.)
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@NogDogAug 18.2010 — PS: Don't forget to consider some sort of caching mechanism, especially if you don't expect the directory data to be changing minute to minute.
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