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@NogDogJul 13.2010 — #I would use the b word boundary assertion, and maybe do something like:
Of course, if someone were to enter "To be or not to be, that is the question." you would end up with "not-,-question.", which may not be what you want. ?@NogDogJul 13.2010 — #
Just to clarify for anyone else who comes along to read this thread, the "b" assertion does [I]not[/I] match the white-space character (or other characters that it considers as a boundary indicator). It [I]asserts[/I] that there is such a boundary condition there but does not include anything in the match. You can think of it as matching the zero-length point between the matched character and the white-space, punctuation, or start/end of string if that makes it easier to deal with.
[RESOLVED] Regex help needed
[code=php]if (!isset($slug)) {
$slug = strtolower($title);
//replaces a word with spaces on either sides
$slug = preg_replace(‘/s(a)|(an)|(and)|(are)|(as)|(at)|(be)|(by)|(com)|(for)|(from)|(i)|(in)|(is)|(it)|(of)|(on)|(or)|(that)|(the)|(this)|(to)|(was)|(what)|(when)|(where)|(who)|(will)|(with)|(you)|(your)s/i’,’ ‘,$slug);
//the last word in the title
$slug = preg_replace(‘/s(a)|(an)|(and)|(are)|(as)|(at)|(be)|(by)|(com)|(for)|(from)|(i)|(in)|(is)|(it)|(of)|(on)|(or)|(that)|(the)|(this)|(to)|(was)|(what)|(when)|(where)|(who)|(will)|(with)|(you)|(your)$/i’,”,$slug);
//the first word in the title
$slug = preg_replace(‘/^(a)|(an)|(and)|(are)|(as)|(at)|(be)|(by)|(com)|(for)|(from)|(i)|(in)|(is)|(it)|(of)|(on)|(or)|(that)|(the)|(this)|(to)|(was)|(what)|(when)|(where)|(who)|(will)|(with)|(you)|(your)s/i’,”,$slug);
$slug = preg_replace(‘/s+/’,’-‘,$slug);
}
$slug = mysql_real_escape_string($slug);
The script supposedly removes all stopwords from a string, but I can’t get it to work. The string “the profile I like is fun” becomes “-pr-le-l-ke-s-fun” after passing through this script, when it’s suppose to become “profile-like-fun”. Help?
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@NogDogJul 13.2010 — #I would use the b word boundary assertion, and maybe do something like:[code=php]
$slug = 'the profile I like is fun';
$regexp = '/b(a|an|and|are|as|at|be|by|com|for|from|i|in|is|it|of|on|or|that|'.
'the|this|to|was|what|when|where|who|will|with|you|your)b/i';
$slug = preg_replace($regexp, '', $slug);
$slug = preg_replace('/s+/', '-', trim($slug));
echo $slug;
[/code]Of course, if someone were to enter "To be or not to be, that is the question." you would end up with "not-,-question.", which may not be what you want. ?
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@NogDogJul 13.2010 — #Never mind, I got it.[/QUOTE]
Just to clarify for anyone else who comes along to read this thread, the "b" assertion does [I]not[/I] match the white-space character (or other characters that it considers as a boundary indicator). It [I]asserts[/I] that there is such a boundary condition there but does not include anything in the match. You can think of it as matching the zero-length point between the matched character and the white-space, punctuation, or start/end of string if that makes it easier to deal with.