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Date calculation help

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Apr 28.2010

Hi all

Using this code, I expect to see the $difference to be number 3 but it returns as 4 which is wrong:

[code=php]
$difference = strtotime(‘2010-04-01’) – strtotime(‘2010-04-03’);
echo $difference/(60*60*12);
[/code]

If I use this however (note the second date is 2010-04-02)

[code=php]
$difference = strtotime(‘2010-04-01’) – strtotime(‘2010-04-02’);
echo $difference/(60*60*12);
[/code]

$difference returns as 2 which is correct.

Why is this not working for the first calculation?

Thanks for helping

p.s. those who are wondering what I am trying to achieve, I just need to calculate the number of days difference between two dates!!

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PHP

1 Comments(s) ↴

Copy linkTweet thisAlerts:
@NogDogApr 28.2010 — I'm confused: you are dividing by 12 hours, but a day has 24 hours. Therefore the results make sense since there are two 12-hour increments per day, and in the first example you have a difference of 2 days multiplied by 2 12-hour periods per day.
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