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@NogDogMay 13.2009 — #I'd just use str_ireplace() in this case (or str_replace()) if using PHP 4):
If you really feel the urge to use preg_replace(), there's no need to match/copy the stuff before the closing tag, and in fact the closing tag could be a look-ahead assertion:
@NogDogMay 13.2009 — #Try this:
@NogDogMay 13.2009 — #Worked OK for me:
@NogDogMay 14.2009 — #Yet another case of requirements creep. :p
@NogDogMay 14.2009 — #Sorry, I tested with a sinlge-line string. Add the "s" modifier:
@NogDogMay 14.2009 — #This was my test case, so that you can see if I'm understanding the requirement or not.
Output;
@NogDogMay 14.2009 — #
You're welcome.
BTW, while I agree with Charles in general principle, in practical fact it can be so much easier to do with a regexp and a single function call, that I will often take the easy way out, especially if it is not a mission-critical functionality.
Simple regular expression
Hi there,
I’m new to regular expressions. I’d really appreciate it if anyone could offer some assistance on a presumably simple regular expression that I can’t seem to figure out.
I’m looking to insert a raquo just before the </p> of the last paragraph in a string to suggest that an article is continued. In so many words, I’d like…
[code]
<p>This is the first paragraph.</p>
<p>This is the second and last paragraph.</p>
… to become…
[code]
<p>This is the first paragraph.</p>
<p>This is the second and last paragraph. »</p>
I’ve been using preg_replace in an attempt to accomplish this seemingly simple task, but to little avail. Apparently it applies to some strings, but not all – I’ve no idea why.
[code]preg_replace(“/(.*)</p>$/”, “$1 »</p>”, $entry->introduction);
If anyone could shed some lights on why exactly the pattern needs to be enclosed in / as well, I’d appreciate.
Thanks! 🙂
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@NogDogMay 13.2009 — #I'd just use str_ireplace() in this case (or str_replace()) if using PHP 4):[code=php]
$text = str_ireplace('</p>', '»</p>', $text);
[/code]If you really feel the urge to use preg_replace(), there's no need to match/copy the stuff before the closing tag, and in fact the closing tag could be a look-ahead assertion:
[code=php]
$text = preg_replace('#(?=</p>)#i', '»', $text);
[/code]0
@NogDogMay 13.2009 — #Try this:[code=php]
$text = preg_replace('#(?=</p>s*$)#i', '»', $text);
[/code]0
@NogDogMay 13.2009 — #Worked OK for me:[code=php]
<?php
$text = "<p>this is a test</p><p>it is only a test</p>";
$text = preg_replace('#(?=</p>s*$)#i', '»', $text);
echo htmlspecialchars($text);
?>
[/code]0
@NogDogMay 14.2009 — #Yet another case of requirements creep. :p[code=php]
$text = preg_replace('#</p>(?!.*</p>)#i', '»</p>', $text);
[/code]0
@NogDogMay 14.2009 — #Sorry, I tested with a sinlge-line string. Add the "s" modifier:<i>
</i>'#</p>(?!.*</p>)#i[B][COLOR="Red"]s[/COLOR][/B]'
0
@NogDogMay 14.2009 — #This was my test case, so that you can see if I'm understanding the requirement or not.[code=php]
<pre><?php
$text = <<<EOD
<p>This is a test.</p>
<p>It is only a test</p>
<div>I am not a paragraph.</div>
EOD;
$text = preg_replace('#</p>(?!.*</p>)#is', '»</p>', $text);
echo htmlspecialchars($text);
?></pre>
[/code]Output;
<i>
</i><p>This is a test.</p>
<p>It is only a test&raquo;</p>
<div>I am not a paragraph.</div>
0
@NogDogMay 14.2009 — #I restarted Apache and somehow now your latest edition of the regular expression works. Thanks so much NogDog.[/QUOTE]
You're welcome.
BTW, while I agree with Charles in general principle, in practical fact it can be so much easier to do with a regexp and a single function call, that I will often take the easy way out, especially if it is not a mission-critical functionality.