[B]I have some code(below) that the INSERT function wont work. The error message displayed is:[I] “Fatal error</b>: Uncaught exception ‘com_exception’ with message ‘Error [0x8002000e] Invalid number of parameters.”
Code:
<?
if ($a == 1)
{
echo “<script type=’text/javascript’> n”;
echo “var temp1; n”;
echo “total; n”;
echo “var total = 0; n”;
echo “var x = 0; n”;
echo “for (counter=0;counter<3;counter++){ n”;
echo “x = x + 1; n”;
echo “var temp3 = ‘colid’ + x; n”;
echo “var content=document.getElementsByTagName(temp3) n”;
echo “temp1 = content[0]; n”;
echo “for(c=0;c<content.length;c++) { n”;
echo “var temp4 = 1; n”;
echo “for(d=0;d<content.length;d++){ n”;
echo “if (c == d) {} n”;
echo “else{ n”;
echo “if (content[d].innerHTML == content[c].innerHTML) { n”;
echo “total = total + 1; n”;
echo “} n”;
echo “} n”;
echo “} n”;
echo “} n”;
echo “} n”;
[COLOR=”Red”][B]echo “$rS2 = $db_conn->execute(“INSERT INTO TempData(Col1) VALUES(‘total’)”);n”;
echo “</script>n”;
}
?>