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@NogDogFeb 17.2011 — #In other words, for whatever reason, [b]$holidays[/b] is not an array -- which could possibly be because it is not defined in the global scope at all, but no way to be sure at this point. This is another good argument for not using [b]global[/b] and instead passing it as a function parameter (either by copy or by reference as needed). You might also want to code defensively then and check to see if it is an array before proceeding, either throwing an exception or returning false if it is not.
Warning: in_array() [function.in-array]: Wrong datatype for second argument
Newbie question: I have a small snipet of code here
$filetype_img = array(“gif”, “jpg”, “jpeg”, “png”, “bmp”, “psd”, “psp”, “tif”);
if(in_array ($fileext, $filetype_img))
{
$filemime = “Image”;
$file_image = $icon_image;
}
The above code works great if it not in a function. Below throws the Warning: in_array() [function.in-array]: Wrong datatype for second argument
function getfileext($fileext){
if(in_array ($fileext, $filetype_img)){
$filemime = “Image”;
$file_image = $icon_image;
}
}
getfileext($ext); // $ext is a string value
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@NogDogFeb 17.2011 — #In other words, for whatever reason, [b]$holidays[/b] is not an array -- which could possibly be because it is not defined in the global scope at all, but no way to be sure at this point. This is another good argument for not using [b]global[/b] and instead passing it as a function parameter (either by copy or by reference as needed). You might also want to code defensively then and check to see if it is an array before proceeding, either throwing an exception or returning false if it is not.