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[RESOLVED] Break if no file found in directory

Good day to you,
I have a function which return an array of files.
I would need it to break if there is no file in the directory.

Here is the code :

[code=php]function compileList($extensions)
{
if ($handle = opendir(‘.’)) {
while (false !== ($file = readdir($handle)))
{
$ext = strtolower(end(explode(‘.’, $file)));

if (in_array($ext, $extensions) AND $file != “.” AND $file != “..”)
{
$files[$file]=implode(file($file));
}
}
closedir($handle);
}
return $files;

}[/code]

Thanks !

to post a comment
PHP

2 Comments(s)

Copy linkTweet thisAlerts:
@ratcatemeNov 17.2008 — replace
[code=php]return $files; [/code]
with
[code=php]if(is_array($files)){
return $files;
}else{
return;
}[/code]


Scott.
Copy linkTweet thisAlerts:
@PeuplarchieauthorNov 17.2008 — Thanks !

that was what I was looking for.

I knew there was an else but I didn't figure how and where, after many trial !
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