/    Sign up×
Community /Pin to ProfileBookmark

simple function to change values of variables

Hi, I’ve got a load of variables which I want to change the values of. The variables are either empty / don’t exist or contain the value ‘YES’. If they contain the value ‘YES’ I want to leave them alone but if they are empty I want to give them the value of ‘NO’.

If i do this it works

[code=php]if (!$var){
$var = “NO”;
}[/code]

so I want to write a function that can process multiple variables, and if I do this it doesn’t work:

[code=php]function yesno($value){
if (!$value){
$value = “NO”;
}
}

yesno($var1);
yesno($var2);[/code]

I’m assuming that using $value as a placeholder in the function suddenly gets confused with being a real variable when I put $value = “NO”;

I’m sure it’s pretty simple, I just can’t think what to search for as a work around.

Thanks

to post a comment
PHP

1 Comments(s)

Copy linkTweet thisAlerts:
@stephan_gerlachNov 05.2008 — you need to return the new value.

[code=php]
function yesno($value){
if (!$value){
return "NO";
}
}

$var1 = yesno($var1);
$var2 = yesno($var2);
[/code]
×

Success!

Help @cannon303 spread the word by sharing this article on Twitter...

Tweet This
Sign in
Forgot password?
Sign in with TwitchSign in with GithubCreate Account
about: ({
version: 0.1.9 BETA 5.6,
whats_new: community page,
up_next: more Davinci•003 tasks,
coming_soon: events calendar,
social: @webDeveloperHQ
});

legal: ({
terms: of use,
privacy: policy
});
changelog: (
version: 0.1.9,
notes: added community page

version: 0.1.8,
notes: added Davinci•003

version: 0.1.7,
notes: upvote answers to bounties

version: 0.1.6,
notes: article editor refresh
)...
recent_tips: (
tipper: @Yussuf4331,
tipped: article
amount: 1000 SATS,

tipper: @darkwebsites540,
tipped: article
amount: 10 SATS,

tipper: @Samric24,
tipped: article
amount: 1000 SATS,
)...