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[RESOLVED] Using PIPE " | " in exec

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Feb 21.2008

Hello, I am trying to pass some text off to an application via the PIPE function in terminal (Unix). The way I am trying to do it is like so:

exec(‘echo -n “sometext” | someapp’);

However, the text doesn’t seem to get piped to the app..

Any ideas?

Thanks in advanced!
Kyle

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PHP

3 Comments(s) ↴

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@NogDogFeb 21.2008 — Could be a [url=http://www.php.net/manual/en/features.safe-mode.php]safe_mode[/url] issue. As per the [url=http://www.php.net/manual/en/function.exec.php]exec() page[/url]:
[B]
[CENTER][SIZE="3"]Warning[/SIZE][/CENTER]
[/B]

With safe mode enabled, the command string is escaped with escapeshellcmd(). Thus, [FONT="Courier New"]echo y | echo x[/FONT] becomes [FONT="Courier New"]echo y | echo x[/FONT].[/quote]
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@Kyleva2204authorFeb 21.2008 — I am not using safe mode, however.. I think that something is getting piped becaues if nothing is getting piped it asks for something.. but its not asking, so something is getting piped just not what I told it. the actual thing is

$query = 'echo -n "' . $thepass .'" | hdiutil attach -stdinpass ~/Desktop/encrypted.dmg';

echo $query . "n";

exec($query);

Thanks
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@Kyleva2204authorFeb 21.2008 — Figured it out, for some reason it didnt work with the -n and the -stdinpass.. IDK why, anywho thanks for anyone that was htinking about it ?
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