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Code explanation

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Dec 25.2007

Possible a stupid question, but is the following code like an if statement? The only parts that confuse me are the ? and : If anyone could explain that I would be grateful. Thank you.

[code=php](!empty($_GET[‘pn’])) ? preg_replace(‘/[^0-9]/’, ”, $_GET[‘pn’]) : null ;[/code]

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PHP

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@tfk11Dec 25.2007 — It's similar yes.

If the expression preceding the question mark evaluates to true then the value of the expression after the question mark is returned else the value of the expression after the colon is returned.

true === (true) ? (true) : (false);

false === (false) ? (true) : (false);
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@EJMAES1973authorDec 25.2007 — Ok, Thank you. Does this have a specific name, or is it just kind of there?
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@ZeroKilledDec 25.2007 — is named as ternary conditional expression, however is commonly named as ternary operator. for more reference http://en.wikipedia.org/wiki/%3F:
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@EJMAES1973authorDec 25.2007 — Alright, thank you for the help.
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@NogDogDec 25.2007 — Also see the manual: http://www.php.net/ternary. (Scroll down 2-3 screens and you'll find the "Ternary Operator" heading.)
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