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conditional operator ?:

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Dec 20.2007

Hi,
I would like to get into the habit of using the ?: operator more often but alas,
I can’t seem to ever make it work and revert to a more familiar habit of IF
So, what is the wrong with the code here?

[code=php]function refile(x){
(x.charAt(0)==’C’) ? x=’file:///’+x.replace(/\/g, “/”); return x : return x;

// if(x.charAt(0)==’C’){ x=’file:///’+x.replace(/\/g, “/”); return x}
// else{return x}

}[/code]

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JavaScript

3 Comments(s) ↴

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@JMRKERDec 20.2007 — First, while I'm not positive about this, I believe you cannot have 2 statements in one assignment.

Second, in your commented out section, there is no need for the extra 'return x'

Could just as easily been coded:

if (...) { x=...}

return x;
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@samliewDec 20.2007 — try

(x.charAt(0)=='C')</URL> ? x='file:///'+x.replace(//g, "/") : void(0);<br/>
return x;

also, in your second piece of code, you could just do this

if(x.charAt(0)=='C') x='file:///'+x.replace(//g, "/");

return x;
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@Declan1991Dec 21.2007 — or
[code=php]
x = (condition)?value:null;
[/code]
That is the normal way to do it.
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