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call an array value that is outside current function

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Aug 24.2007

I’m trying to compare an array value within a function. The problem is, the array is outside the function and it doesn’t recognize the value. I think I can put $_server or $_get in front of $colors, but I can’t find any good examples. Can someone help me with my script below.

<?php
$doQuery = mysql_query(“SELECT data FROM usersettings WHERE user = ‘$friendID1′”)
or die(mysql_error());

$colors=mysql_fetch_array($doQuery);

[COLOR=”Red”]$colors[/COLOR]=unserialize($colors[‘data’]);

?>
————————————————————————

<?php
function Fetcher3()
{
echo [COLOR=”Red”]$colors[/COLOR][‘randompicwidth’];
}
Fetcher3();
?>

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PHP

5 Comments(s) ↴

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@stephan_gerlachAug 24.2007 — How about this?

[code=php]

<?php
$doQuery = mysql_query("SELECT data FROM usersettings WHERE user = '$friendID1'")
or die(mysql_error());

$colors=mysql_fetch_array($doQuery);

$colors=unserialize($colors['data']);
?>
------------------------------------------------------------------------
<?php
function Fetcher3($colors)
{
echo $colors['randompicwidth'];
}
Fetcher3($colors);
?>



[/code]
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@lehulaauthorAug 24.2007 — the problem is, i have many values from the array I want to grab, not just that one. Probably about 60+ values. So putting that wouldn't be practical. thanks though
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@artemisAug 24.2007 — [code=php]
$doQuery = mysql_query("SELECT data FROM usersettings WHERE user = '$friendID1'")
or die(mysql_error());

$colors=mysql_fetch_array($doQuery);

$colors=unserialize($colors['data']);

------------------------------------------------------------------------

function Fetcher3(){
global $colors; # Add this line
echo $colors['randompicwidth'];
}
Fetcher3();
[/code]
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@lehulaauthorAug 24.2007 — awsome, thankyou
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@NogDogAug 24.2007 — While the global solution will work, it can be a maintenance nightmare. I would recommend simply supplying the array as a parameter of the function:
[code=php]
function Fetcher3($colors){
echo $colors['randompicwidth'];
}
Fetcher3($colors);
[/code]
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