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displayibg the result of a basename()

Good day to you all,
in the following line, .basename($newpath2);. is not acting correctly it should, take $newpath2 and extract the basename, no extension, and input the result in the javascript by replacing .basename($newpath2);.

This is one wayI have done it .

[code=php]

echo ‘<OPTION onClick=”blocking(‘.basename($newpath2);.’);” return true;”>’.substr($newpath, 7).'</option>’;

[/code]

here is another way I have tried

[code=php]

echo ‘<OPTION onClick=”blocking(‘<?php echo basename($newpath2);?>’);” return true;”>’.substr($newpath, 7).'</option>’;

[/code]

Do somebody would know what i’m doing wrong ?
Thanks !

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JavaScript

1 Comments(s)

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@DokJul 20.2007 — You should post this question in the PHP forum - it is not a JavaScritp issue.
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