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preg_replace

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Jun 07.2007

hi

i have one mysql table which has 2 fields

1.id 2.message

values

1 r%#dfont style=”font-size: 8pt;”#i#j# WELCOME r%#d/fontb*%d

i want to fetch this data and print it as WELCOME

i want to replace r%#d with ‘<‘ and b*%d with ‘>’ and ignore this #i#j#.
i have used preg_replace but nothing is displaying.any of your help will be appreciated.

thanks
mrjameer

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PHP

3 Comments(s) ↴

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@bokehJun 07.2007 — What did you try?
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@roshanjameerauthorJun 07.2007 — i tried the following one

$row['message'] = preg_replace( "((http)+(s)?:(//)|(www.))((w|.|-|_)+)(/)?(S+)?i", "r%#da target="_blank" href="http3://5689" title="0"b*%d56r%#d/ab*%d", $row['message']);

thanks

mrjameer
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@bokehJun 07.2007 — Can you explain why you believe this pattern:[QUOTE=roshanjameer]((http)+(s)?:(//)|(www.))((w|.|-|_)+)(/)?(S+)?[/QUOTE]has any relationship with this?r%#dfont style="font-size: 8pt;"#i#j# WELCOME r%#d/fontb*%d[/QUOTE]
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